关于“巧用均值不等式求条件分式最值”的再讨论

李老师在文[1]中使用均值不等式来求解几类条件分式最值问题.但其求解过程较繁琐,构造性太强,因而不易为中学生所理解、掌握.本文重新考虑了文[1]中几类问题,通过权方和不等式给出了他们的简单证明.     

用琴生不等式证明一类含“abc=1”条件的不等式

在诸多证明不等式的问题中,笔者发现一些含"abc=1"条件的不等式用琴生不等式来证明很简     

关于“巧用均值不等式求条件分式最值”的再讨论

李老师在文[1]中使用均值不等式来求解几类条件分式最值问题．但其求解过程较繁琐，构造性太强，因而不易为中学生所理解、掌握．     

A new method for the synthesis of 3-hydroxymethylbenzofuran

A new one-step synthesis of 3-hydroxymethylbenzofuran, based on intramolecular cyclization of 2- （methoxymethyl）-2-（2＇-methoxymethyl-4＇-methylphenyl）-butanone I under diluted hydrochloric acid in THF, was developed. The mechanism for this process was investigated via chemical equilibrium shift of tautomer in acidic conditions. The applicability of this new method was studied further in this paper.     

半定矩阵秩极小的非凸精确松弛

本文主要研究半定矩阵秩极小问题(P)的非凸精确松弛及其性质.首先,为求解问题(P),我们引入其Schatten p-范数(0＜p＜1)松弛,记为(Sp).其次,通过定义半定限制等距常数和半定限制正交常数,我们给出了问题(P)有唯—解的充分条件.最后,利用半定限制等距性质,我们给出了问题(P)和(Sp)有相同唯一解的充分条件.特别地,对任意0＜p＜1,我们还得到—个一致的精确恢复条件.     

两角和正切公式与韦达定理

点评求角要通过求值和判断角的范围两步来完成．确定角的范围是关键，有时注意隐含条件，缩小角的范围．     

向量回路法简解竞赛题

例1(第23届"希望杯"全国数学邀请赛培训题高一41题)△ABC中,已知AB=4,BC=5,AC=6,若点O是△ABC的外心,则→AO.→AC的值是.分析标准解答给出的解法是应用余弦定理、正弦定理和向量数量积的定义,繁琐冗长.事实上,若注意到题设条件AC=6及向量回路A→M→O,便有如下简解.简解取AC的中点M,则必有MO⊥AC,     

Investigation of unique hue setting changes with ageing

Clromatic sensitivity along the protan, deutan, and tritan lines and the loci of the unique hues (red, green, yellow, blue) for a very large sample (n = 185) of colour-normal observers ranging from 18 to 75 years of age are assessed. Visual judgments are obtained under normal viewing conditions using colour patches on self-luminous display under controlled adaptation conditions. Trivector discrimination thresholds show an increase as a function of age along the protan, deutan, and tritan axes, with the largest increase present along the tritan line, less pronounced shifts in unique hue settings are also observed. Based on the chromatic (protan, deutan, tritan) thresholds and using scaled cone signals, we predict the unique hue changes with ageing. A dependency on age for unique red and unique yellow for predicted hue angle is found. We conclude that the chromatic sensitivity deteriorates significantly with age, whereas the appearance of unique hues is much less affected, remaining almost constant despite the known changes in the ocular media.     

尝试一题多解 锤炼解题能力

对于做题目,我们不要仅仅局限于会做,关键是要从做题目的过程中,掌握方法、深化知识.例1已知x满足x2-3x+1=0,求x+1x的值.方法1直接从已知条件入手,用求根公式求出x的值,再代入求值即可.