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1.
For a set A of nonnegative integers, the representation functions R2(A,n) and R3(A,n) are defined as the numbers of solutions to the equation n = a + a′ with a,a′∈ A, a < a′ and a a′, respectively. Let N be the set of nonnegative integers. Given n0 > 0, it is known that there exist A,A′■ N such that R2(A′,n) = R2(N \ A′,n) and R3(A,n) = R3(N \ A,n) for all n n0. We obtain several related results. For example, we prove that: If A ■ N such that R3(A,n) = R3(N \ A,n) for all n n0, then (1) for any n n0 we have...  相似文献   

2.
数论问题     
本讲通过数学竞赛中的一些数论问题,简要地介绍初等数论中较为基本的思考方法.对于问题所涉及的数论基础知识,我们将直接引用而不作讨论(可以参看,例如,《奥数教程》,高三年级,华东师范大学出版社) .例1 设a ,b是给定的正整数,证明,仅有有限多个正整数n ,使得(a + 12 ) n+ (b + 12 ) n为整数.证 问题等价于证明,仅有有限多个n ,使得2 n整除(2a + 1) n+ (2b + 1) n.我们希望分解被除数(2a + 1) n+ (2b + 1) n.这在n为奇数时易于实现:我们有(2a + 1) n + (2b + 1) n =(2a + 2b + 2 ) (2a +1) n -1- (2a + 1) n -2 (2b + 1) +…- (2a + 1) (2…  相似文献   

3.
张兰庆 《数学通报》2001,(10):33-35
众所周知,在实数系,符号n(√a)有明确的意义:如果a>0,n(√a)表示一个正数,它的n次方等于a,即n(√a)>0,且(n(√a))n=a.这时,n(√a)表示a的n次算术根.如果a=0,n(√a)=0,如果a<0.当n是奇数时,n(√a)=-n(√-a)这里的n(√-a)是正数-a的n次算术根,当n是偶数时,n(√a)没有意义.  相似文献   

4.
(a b)n展开式的系数表是杨辉三角.本文试对(a b c)n展开式的系数具有怎样的结构和性质进行探讨.1 (a b c)n展开式的一个系数表先看n=1,2,3,4,5,6时(a b c)n展开式的系数(表1).表1n(a b c)n展开式各项的系数11,1,121,1,1,2,2,231,1,1,3,3,3,3,3,3,641,1,1,4,4,4,4,4,4,6,6,6,12  相似文献   

5.
F.Smarandache的一个问题   总被引:8,自引:2,他引:6  
设 n是正整数 ,a( n)表示 n的三次方幂补数 .本文的主要目的是研究 a( n)和 a( n)n 的 k次均值性质 ,解决 F.Smarandache教授提出的第 2 8个问题 ,并用解析方法给出两个有趣的渐近公式  相似文献   

6.
题155设f(n,p)=C2pn(n,p∈N,p≤2n).数列{a(n,p)}满足a(1,p) a(2,p) … a(n,p)=f(n,p).1)求证:{a(n,2)}是等差数列;2)求证:f(n,1) f(n,2) … f(n,n)=22n-1 21C2nn-1;3)设函数H(x)=f(n,1)x f(n,2)x2 … f(n,2n)·x2n,试比较H(x)-H(a)与2n(1 a)2n-1(x-a)的大小.解1)由a(1,2) a(2,  相似文献   

7.
对任意的正整数m和一个确定的正整数r(r≥3),a(n)、b(n)为r是数上下补数序列,利用初等方法和解析方法,给出了a(n)、b(n)与三个数论函数(n)、V(n)和e_p(n)的复合函数(a(n))、(b(n)),V(a(n))、V(b(n))及e_p(a(n))、e_p(b(n))的均值,获得了准确的渐近公式,发展了相关问题的研究工作.  相似文献   

8.
与二项式系数有关的求和问题的解题策略   总被引:1,自引:0,他引:1  
1赋值求和例1设(2x-3)10=a10(x-1)10 a9(x-1)9 … a2(x-1)2 a1(x-1) a0,求a1 a2 a3 … a10的值.解令x=2,得a0 a1 a2 a3 … a10=1;令x=1,得a0=(-1)10=1,所以a1 a2 a3 … a10=1-1=0.例2设(1 x x2)n=a0 a1x a2x2 … a2nx2n,求a1 a3 a5 … a2n-1的值.解令x=1,得a0 a1 a2 … a2n=3n;令x=-1,得a0-a1 a2-…-a2n-1 a2n=1.两式相减得a1 a3 a5 … a2n-1=3n-12.2逆用定理例3已知等比数列{an}的首项为a1,公比为q,求和:a1C0n a2C1n a3C2n … an 1Cnn.解a1C0n a2C1n a3C2n … an 1Cnn=a1C0n a1qC1n a1q2C2n … a1qnCnn=a1(C0n qC1n q2C2n … qnCnn)…  相似文献   

9.
令N表示全体非负整数的集合.对给定的集合A C N及n∈N,令R_1(A,n)表示方程n=a+a',a,a'∈A的解的个数.令R_2(A,n)和R_3(A,n)分别表示方程n=a+a',a,a'∈A在条件aa'和a≤a'下解的个数.一个有趣的问题是:给定i∈{1,2,3},确定所有非负整数集合对(A;B),使其表示函数R_i(A,n)及R_i(B,n)最终相等.文章讨论了相关问题.  相似文献   

10.
对任意正整数n,我们定义a(n)为n的平方补数,即a(n)表示能够使na(n)为完全平方数的最小正整数.本文的主要目的是利用初等方法研究方程a(n1)+a(n2)+…+a(nk)=m·a(n1+n2+…+nk)的可解性,并证明对某些特殊的正整数m及任意正整数k>1,该方程有无穷多组正整数解(n1,n2,…,nk).  相似文献   

11.
构造了随机自相似分形及其上的记忆函数,并得出了有关结论,在此基础上,我们可以定义一个随机概率测度dΦn(τ)=Kn(τ)dτ,Φn(τ)弱收敛于Φ,进一步可得到强测度序列Ψn(·)=EΦn(·),则{Ψn}弱收敛于Ψ=EΦ.  相似文献   

12.
设E是具弱序列连续对偶映像自反Banach空间, C是E中闭凸集, T:C→ C是具非空不动点集F(T)的非扩张映像.给定u∈ C,对任意初值x0∈ C,实数列{αn}n∞=0,{βn}∞n=0∈ (0,1),满足如下条件:(i)sum from n=α to ∞α_n=∞, α_n→0;(ii)β_n∈[0,α) for some α∈(0,1);(iii)sun for n=α to ∞|α_(n-1) α_n|<∞,sum from n=α|β_(n-1)-β_n|<∞设{x_n}_(n_1)~∞是由下式定义的迭代序列:{y_n=β_nx_n (1-β_n)Tx_n x_(n 1)=α_nu (1-α_n)y_n Then {x_n}_(n=1)~∞则{x_n}_(n=1)~∞强收敛于T的某不动点.  相似文献   

13.

We investigate the asymptotic behavior of solutions of the system x ( n +1)=[ A + B ( n ) V ( n )+ R ( n )] x ( n ), n S n 0 , where A is an invertible m 2 m matrix with real eigenvalues, B ( n )= ~ j =1 r B j e i u j n , u j are real and u j p ~ (1+2 M ) for any M ] Z , B j are constant m 2 m matrices, the matrix V ( n ) satisfies V ( n ) M 0 as n M X , ~ n =0 X Á V ( n +1) m V ( n ) Á < X , ~ n =0 X Á V ( n ) Á 2 < X , and ~ n =0 X Á R ( n ) Á < X . If AV ( n )= V ( n ) A , then we show that the original system is asymptotically equivalent to a system x ( n +1)=[ A + B 0 V ( n )+ R 1 ( n )] x ( n ), where B 0 is a constant matrix and ~ n =0 X Á R 1 ( n ) Á < X . From this, it is possible to deduce the asymptotic behavior of solutions as n M X . We illustrate our method by investigating the asymptotic behavior of solutions of x 1 ( n +2) m 2(cos f 1 ) x 1 ( n +1)+ x 1 ( n )+ a sin n f n g x 2 ( n )=0 x 2 ( n +2) m 2(cos f 2 ) x 2 ( n +1)+ x 2 ( n )+ b sin n f n g x 1 ( n )=0 , where 0< f 1 , f 2 < ~ , 1/2< g h 1, f 1 p f 2 , and 0< f <2 ~ .  相似文献   

14.
立方幂补数除数函数的均值   总被引:7,自引:0,他引:7  
设 n是正整数 ,S(n)是 n的立方幂补数 ,τ(n)表示 n的除数函数 .本文的主要目的是探讨∑n xτ(S(n) )n 和 ∑n xτ(S(n) ) 的渐近性质 ,得到了两个渐近公式 ,进一步解决 F.Smarandache教授提出的第2 8个问题 .  相似文献   

15.
An oriented tetrahedron is a set of four vertices and four cyclic triples with the property that any ordered pair of vertices is contained in exactly one of the cyclic triples. A tetrahedral quadruple system of order n (briefly TQS(n)) is a pair (X,B), where X is an nelement set and B is a set of oriented tetrahedra such that every cyclic triple on X is contained in a unique member of B. A TQS(n) (X,B) is pure if there do not exist two oriented tetrahedra with the same vertex set. In this paper, we show that there is a pure TQS(n) if and only if n = 2,4 (mod 6), n > 4, or n = 1,5 (mod 12). One corollary is that there is a simple two-fold quadruple system of order n if and only if n = 2,4 (mod 6) and n > 4, or n = 1,5 (mod 12). Another corollary is that there is an overlarge set of pure Mendelsohn triple systems of order n for n=1,3 (mod 6), n > 3, or n =0,4 (mod 12).  相似文献   

16.
A idempotent quasigroup (Q, o) of order n is equivalent to an n(n-1)×3 partial orthogonal array in which all of rows consist of 3 distinct elements. Let X be a (n+1)-set. Denote by T(n+1) the set of (n+1)n(n-1) ordered triples of X with the property that the 3 coordinates of each ordered triple are distinct. An overlarge set of idempotent quasigroups of order n is a partition of T(n+1) into n+1 n(n-1)×3 partial orthogonal arrays A_x, x∈X based on X\{x}. This article gives an almost complete solution of overlarge sets of idempotent quasigroups.  相似文献   

17.

The authors consider m -th order nonlinear difference equations of the form D m p x n + i h j ( n , x s j ( n ) )=0, j =1,2,( E j ) where m S 1, n ] N 0 ={0,1,2,…}, D 0 p x n = x n , D i p x n = p n i j ( D i m 1 p x n ), i =1,2,…, m , j x n = x n +1 m x n , { p n 1 },…,{ p n m } are real sequences, p n i >0, and p n m L 1. In Eq. ( E 1 ) , p = a and p n i = a n i , and in Eq. ( E 2 ) , p = A and p n i = A n i , i =1,2,…, m . Here, { s j ( n )} are sequences of nonnegative integers with s j ( n ) M X as n M X , and h j : N 0 2 R M R is continuous with uh j ( n , u )>0 for u p 0. They prove a comparison result on the oscillation of solutions and the asymptotic behavior of nonoscillatory solutions of Eq. ( E j ) for j =1,2. Examples illustrating the results are also included.  相似文献   

18.
华罗庚  陆启铿 《数学学报》1959,9(3):306-314
<正> 3.1.斜对称方阵双曲空间的调和函数 命 Z 代表 n×n 斜对称方阵(?)(?)个复变数 z_(12),z_(13),…z_(1n),z_(23),…,(?)…,z_(n-1,n)空间的域我们引进运算子  相似文献   

19.
研究I(x,n(x))=n(x),其中I为由连续三角模T、连续三角余模S和强否定n生成的D-蕴涵,即I(x,y)=S(T(n(x),n(y)),y),给出了满足I(x,n(x))=n(x)的充要条件。  相似文献   

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