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1.
采用密度泛函理论B3LYP/6-31++G(d,p)方法,对纤维素热解的主要产物左旋葡聚糖的热解反应机理进行了理论计算分析,设计了四种可能的热解反应途径, 对各种反应的反应物、产物和过渡态的结构进行了能量梯度全优化。计算结果表明,左旋葡聚糖开环成链状中间体时,首先,左旋葡聚糖中的两个半缩醛键C(1)-O(7)和C(6)-O(8)断裂,经过渡态TS1形成中间体IM1,同时,C(6)-O(7)结合成键使C(5)-C(6)-O(7)形成环状结构,该反应的能垒较高,为296.53 kJ/mol,然后IM1经过渡态TS2转变为中间体IM2,该反应的能垒为234.09 kJ/mol;对IM2设计了四条可能的反应路径,反应路径2和3能垒较低,是IM2最可能的热解反应途径;在反应路径1和4中都包含了脱羰基反应,其反应能垒较高,不易发生。  相似文献   

2.
为了从微观上理解半纤维素热解过程及其主要产物的形成演变机理,采用密度泛函理论方法B3LYP/6-31G++(d,p),对O-乙酰基-吡喃木糖的热解反应机理进行了量子化学理论研究。在热解过程中,O-乙酰基-吡喃木糖中的O-乙酰基首先脱出,形成乙酸和中间体IM1,该步反应能垒为269.4 kJ/mol。IM1进一步发生开环反应形成IM2,开环反应能垒较低,为181.8 kJ/mol。对中间体IM2设计了四种可能的热解反应途径,对各种反应的反应物、产物、中间体和过渡态的结构进行了能量梯度全优化,计算了各热解反应途径的热力学和动力学参数。计算结果表明,反应路径(4)和反应路径(2)是O-乙酰基-吡喃木糖热解的主要反应通道,乙酸、乙醛、乙醇醛、丙酮、CO、CO2、CH4等小分子产物是热解的主要产物。这与相关实验结果分析是一致的。  相似文献   

3.
生物油重质组分模型物热解行为及其动力学研究   总被引:2,自引:0,他引:2  
采用TG-FT-IR在非等温条件下对生物油重质组分酚、醛和糖类模型代表物(丁香酚、香草醛、左旋葡聚糖)进行热解特性及其热解动力学分析。TG-DTG曲线和FT-IR测试数据显示,重质组分模型物热解的先后次序是酚类、醛类、糖类物质。香草醛、丁香酚均为一个主热解阶段,主要产物为水、烷烯烃、CO2、CO和小分子酚、芳香醛。左旋葡聚糖热解分两阶段进行,热解发生在较高温区(180~370℃),主要热解产物有CO2、烷烯烃、醛、酮和环醚,少量的CO和水。混合物热解分为三个阶段,产物与单一模型物热解产物相似,但有少量缩醛低聚物。对比单一组分,混合物中羰基和羟基组分在较高温区(≥300℃)存在相互作用,生成难分解的缩聚物。其中,糖类是影响重质组分热解速率的主要物质。根据热重数据对热解各阶段进行动力学拟合,确定了模型物热解反应动力学三因素。平均表观活化能和反应级数分别为:E左旋葡聚糖第一、第二阶段分别为115.80 kJ/mol(0.5级)、141.19 kJ/mol(2/3级); E混合物第一阶段为54.46 kJ/mol(1级)、第二阶段为50.67 kJ/mol(2/5级); E丁香酚为42.29 kJ/mol(0.7级); E香草醛为36.53 kJ/mol(0.95级)。  相似文献   

4.
丙三醇脱水反应机理的密度泛函理论研究   总被引:1,自引:0,他引:1  
黄金保  刘朝  魏顺安  黄晓露 《化学学报》2010,68(11):1043-1049
为了理解纤维素热解初期的脱水反应机理, 采用Gaussian 03程序中的密度泛函理论UB3LYP/6-31++G(d,p) 方法, 对模型化合物丙三醇脱水反应机理进行了量子化学理论研究. 设计了6种可能的脱水反应途径, 对各种反应的反应物、产物和过渡态的结构进行了能量梯度全优化, 计算了不同温度下各反应途径的标准热力学和动力学参数. 计算结果表明: 除了形成中间体IMa和IMb的反应外, 其它反应均为吸热反应; 温度高于400 K时, 丙三醇开始发生脱水反应; 与1-2-脱水反应相比, 1-3-脱水反应的反应势垒更低, 其活化能为233.75 kJ/mol; 当反应加入金属离子Li时, 有利于脱水反应的发生, 这时1-2-脱水反应的活化能为201.95 kJ/mol, 1-3-脱水反应的活化能为202.14 kJ/mol.  相似文献   

5.
木质素模化物紫丁香酚热解机理的量子化学研究   总被引:3,自引:0,他引:3  
采用密度泛函理论方法B3LYP/6-31G++(d,p),对木质素模化物紫丁香酚的热解反应机理进行了量子化学理论研究。提出了三种可能的热解反应途径,对各种反应的反应物、产物、中间体和过渡态的结构进行了能量梯度全优化。计算了各热解反应途径的标准动力学参数,分析了各种主要热解产物的形成演化机理。键离解能计算结果表明,紫丁香酚中CH3-O键的键离解能最小,各种键离解能的大小顺序为CH3-O < O-H < CH3O-Caromatic < CH2-H < HO-Caromatic < Caromatic-H。在反应路径(1)中,主要热解产物是3-甲氧基邻苯二酚,其形成反应的总能垒为366.6 kJ/mol;在反应路径(2)中主要热解产物是2-甲氧基-6-甲基苯酚,其形成反应的总能垒为474.8 kJ/mol;在反应路径(3)中形成邻甲氧基苯酚的总能垒很低,为21.4 kJ/mol,这表明,在连接甲氧基的碳原子上加氢后能够有效地降低木质素芳环模化物紫丁香酚去甲氧基反应的反应能垒。  相似文献   

6.
乙炔基自由基C2H与氧气反应的密度泛函理论研究   总被引:7,自引:3,他引:4  
应用量子化学从头算和密度泛函理论(DFT)对C2H自由基和O2的反应进行了研究.在B3LYP/6-311G**水平上优化了反应通道上各驻点(反应物、中间体、过渡态和产物)的几何构型,并计算出它们的振动频率和零点振动能(ZPVE).各物种的总能量由CCSD(T)/6-311G**//B3LYP/6-311G**给出,并对能量进行了零点能校正.计算结果表明,反应物中自由基C2H中的边端C进攻O2形成了中间体1 (HCCOO),中间体1是一个加合产物.由中间体1经过不同的反应通道可以生成不同的产物P1 (HCO+CO), P2 (HCCO+O), P3(CO2+CH), P4 (C2O+OH)和P5 (2CO+H).反应通道之间存在着竞争机制.其中P1, P2是主要产物,其次还有一定比例的P5生成,而产物P3, P4的生成几率较低.各条反应通道化学反应热的计算与实验吻合较好.  相似文献   

7.
选用合理简化的焦炭模型,对煤焦燃烧过程中N2O的异相生成和分解机理进行了分子水平上的研究。采用UB3LYP/6-31G(d)密度泛函理论方法优化得到了反应路径上反应物、产物、中间体和过渡态的几何构型和各中间反应的活化能和反应焓变。NO与其预先吸附在焦炭表面解离生成的表面氮组分反应生成N2O的路径有两个,需要克服的势垒分别为69.3kJ/mol和200.0kJ/mol;NO亦可直接与焦炭中的吡啶氮结合释放出N2O,该反应路径所需克服的最大势垒为418.0kJ/mol。N2O可在焦炭表面分解释放出N2,异相分解反应为一步反应,计算所得活化能为100.8kJ/mol。N2O的异相生成和异相分解反应均为放热反应。采用经典过渡态理论计算得到了各路径中速率控制步骤的反应速率常数。低温条件下,N2O的异相分解反应速率略低于其异相生成速率,随着温度的升高,两者逐渐接近,说明高温条件有利于N2O的异相分解。  相似文献   

8.
曲威  王长生 《化学学报》2010,68(21):2186-2190
采用密度泛函理论B3LYP方法研究了蛋白质和水环境下2-磷酸甘油酸脱水生成磷酸烯醇式丙酮酸的反应机理. 优化得到了反应物、过渡态及产物的几何构型并计算了反应势垒. 研究结果表明: 没有H2O参与时, 反应需要通过四元环过渡态完成, 反应势垒高达287.7 kJ/mol, 常温下难以进行|有H2O参与时, 反应可以通过六元环过渡态完成, 反应势垒大为降低|Mg2+的参与可使反应势垒进一步降低|蛋白质环境下两个Mg2+和一个H2O的共同作用可使反应势垒降低至91.2 kJ/mol, 从而使反应在常温下容易进行.  相似文献   

9.
以Ni+与C3H8反应作为过渡金属离子与烷烃反应的范例体系,用B3LYP密度泛函方法计算了[Ni,C3,H8]+基态势能面上各驻点的构型、频率和能量,结果表明,该反应的H2分子消除需经历两个基元步骤,即Ni+首先插入一级或二级C-H键,然后经H转移过渡态异构化为较稳定的中间体,继而解离产生H2分子.计算的反应热为142.28kJ/mol,与相应的实验值(127.85kJ/mol)符合较好.  相似文献   

10.
用半经验AM1法研究了C60与单态硅烯环加成反应机理.经Berny梯度法优化得到反应的过渡态,并进行了振动分析确认.计算结果表明:硅烯在C60的66键上的加成反应分两步,第一步反应物生成中间配合物,无势垒;第二步由中间配合物经过渡态变为产物.65键上的加成反应分三步,第一步由反应物生成中间配合物,第二步由中间配合物经过渡态I得到闭环结构的中间体,第三步由中间体经过渡态Ⅱ形成产物.66键加成反应的活化势垒较低,从反应机理和动力学角度解释了66键加成优于65键加成的原因.  相似文献   

11.
The complex triplet potential energy surface of the C2H3N system is investigated at the UB3LYP and CCSD(T) (single-point) levels in order to explore the possible reaction mechanism of C2H3 radical with N(4S). Eleven minimum isomers and 18 transition states are located. Possible energetically allowed reaction pathways leading to various low-lying dissociation products are obtained. Starting from the energy-rich reactant C2H3+N(4S), the first step is the attack of the N atom on the C atom having one H atom attached in C2H3 radical and form the intermediate C2H3N(1). The associated intermediate 1 can lead to product P1 CH2CN+H and P2 3CH2+3HCN by the cleavage of C–H bond and C–C bond, respectively. The most favorable pathway for the C2H3+N(4S) reaction is the channel leading to P1, which is preferred to that of P2 due to the comparative lower energy barrier. The formation of P3 3C2H2+3NH through hydrogen-abstraction mechanism is also feasible, especially at high temperature. The other pathways are less competitive comparatively.  相似文献   

12.
The pyrolysis mechanism of important intermediate 1-hexene of carbon matrix precursor cyclohexane was studied theoretically. Possible reaction paths were designed based on the potential surface scan and electron structure of the initial C–C bond breaking reactions. Thermodynamic and kinetic parameters of the possible reaction paths were computed by UB3LYP/6-31+G* at different temperature ranges. The results show that 1-hexene pyrolyzes at 873 K. When below 1273 K, the major reaction paths are those that produce C3H4, and above 1273 K, the major reaction paths are those that produce C3H3 from the viewpoint of thermodynamics. From the viewpoint of kinetics, the major product is C3H3, it results from the pyrolysis reaction of 1-hexene cracking bond C3–C4 and generating C3H5 and C3H7 with the activation energy ΔE0θ=296.32 kJ/mol. Kinetic results also show that product C3H4 accompany simultaneously, which is the side reaction starting from the pyrolysis of 1-hexene forming C4H7 and C2H5 with the activation energy of 356.73 kJ/mol. When reaching 1473 K, the rate constant of the rate-determining steps of these two reaction paths do not show much difference, which means both the reaction paths exist in the pyrolysis process at the high temperature. The above results are basically in accordance with mass spectrum analysis and far more specific.  相似文献   

13.
The mechanism of the cycloaddition reaction of forming a silapolycyclic compound between singlet silylidene and formaldehyde has been investigated with MP2/6-31G* method, including geometry optimization and vibrational analysis for the involved stationary points on the potential energy surface. The energies of the different conformations are calculated by CCSD(T)//MP2/6-31G* method. From the potential energy profile, it can be predicted that the cycloaddition reaction process of forming the silapolycyclic compound (P2) for this reaction consists of four steps: (I) the two reactants first form a semi-cyclic intermediate INT1a through a barrier-free exothermic reaction of 32.5 kJ mol−1; (II) this intermediate then isomerizes to an active four-membered ring intermediate INT1 via a transition state TS1a with an energy barrier of 30.8 kJ mol−1; (III) INT1 further reacts with formaldehyde to form an intermediate INT2, which is also a barrier-free exothermic reaction of 30.1 kJ mol−1; (IV) INT2 isomerizes to a silapolycyclic compound P2 via a transition state TS2 with a barrier of 50.6 kJ mol−1. Comparing this reaction path with other competitive reaction paths, we can see that this cycloaddition reaction has an excellent selectivity.  相似文献   

14.
Xiuhui Lu  Xin Che  Leyi Shi  Junfeng Han 《中国化学》2010,28(10):1803-1809
The mechanism of the cycloaddition reaction of forming germanic hetero‐polycyclic compound between singlet germylene carbene and formaldehyde has been investigated with MP2/6‐31G* method, including geometry optimization and vibrational analysis for the involved stationary points on the potential energy surface. The energies of the different conformations are calculated by CCSD (T)//MP2/6‐31G* method. From the potential energy profile, we predict that the cycloaddition reaction of forming germanic hetero‐polycyclic compound between singlet germylene carbene and formaldehyde has two competitive dominant reaction pathways. First dominant reaction pathway consists of four steps: (1) the two reactants (R1, R2) first form an intermediate (INT1) through a barrier‐free exothermic reaction of 117.5 kJ/mol; (2) intermediate (INT1) then isomerizes to a four‐membered ring compound (P2) via a transition state (TS2) with an energy barrier of 25.4 kJ/mol; (3) four‐membered ring compound (P2) further reacts with formaldehyde (R2) to form an intermediate (INT3), which is also a barrier‐free exothermic reaction of 19.6 kJ/mol; (4) intermediate (INT3) isomerizes to a germanic bis‐heterocyclic product (P3) via a transition state (TS3) with an energy barrier of 5.8 kJ/mol. Second dominant reaction pathway is as follows: (1) the two reactants (R1, R2) first form an intermediate (INT4) through a barrier‐free exothermic reaction of 197.3 kJ/mol; (2) intermediate (INT4) further reacts with formaldehyde (R2) to form an intermediate (INT5), which is also a barrier‐free exothermic reaction of 141.3 kJ/mol; (3) intermediate (INT5) then isomerizes to a germanic bis‐heterocyclic product (P5) via a transition state (TS5) with an energy barrier of 36.7 kJ/mol.  相似文献   

15.
The mechanism of the cycloaddition reaction of forming a silapolycyclic compound between singlet methylenesilylene and acetone has been investigated with MP2/6‐31G* method, including geometry optimization and vibrational analysis for the involved stationary points on the potential energy surface. The energies of the different conformations are calculated by CCSD(T)//MP2/6‐31G* method. From the potential energy profile, we predict that the cycloaddition reaction of forming a silapolycyclic compound between singlet methylenesilylene and acetone has two competitive dominant reaction pathways. First dominant reaction pathway consists of four steps: (I) the two reactants (R1, R2) first form an intermediate (INT1) through a barrier‐free exothermic reaction of 46.2 kJ/mol; (II) intermediate (INT1) then isomerizes to a planar four‐membered ring product (P3) via transition state (TS3) with an energy barrier of 47.1 kJ/mol; (III) planar four‐membered ring product (P3) further reacts with acetone (R2) to form an intermediate (INT4), which is also a barrier‐free exothermic reaction of 40.0 kJ/mol; (IV) intermediate (INT4) isomerizes to a silapolycyclic compound (P4) via transition state (TS4) with an energy barrier of 57.0 kJ/mol. Second dominant reaction pathway consists of three steps: (I) the two reactants (R1, R2) first form a four‐membered ring intermediate (INT2) through a barrier‐free exothermic reaction of 0.5 kJ/mol; (II) INT2 further reacts with acetone (R2) to form an intermediate (INT5), which is also a barrier‐free exothermic reaction of 45.4 kJ/mol; (III) intermediate (INT5) isomerizes to a silapolycyclic compound (P5) via transition state (TS5) with an energy barrier of 49.3 kJ/mol. P4 and P5 are isomeric compounds. © 2009 Wiley Periodicals, Inc. Int J Quantum Chem, 2010  相似文献   

16.
The mechanism of the cycloaddition reaction between singlet dichloro‐germylene carbene and aldehyde has been investigated with MP2/6‐31G* method, including geometry optimization and vibrational analysis for the involved stationary points on the potential energy surface. The energies of the different conformations are calculated by zero‐point energy and CCSD (T)//MP2/6‐31G* method. From the potential energy profile, it can be predicted that the reaction has two competitive dominant reaction pathways. The channel (A) consists of four steps: (1) the two reactants (R1, R2) first form an intermediate INT2 through a barrier‐free exothermic reaction of 142.4 kJ/mol; (2) INT2 then isomerizes to a four‐membered ring compound P2 via a transition state TS2 with energy barrier of 8.4 kJ/mol; (3) P2 further reacts with aldehyde (R2) to form an intermediate INT3, which is also a barrier‐free exothermic reaction of 9.2 kJ/mol; (4) INT3 isomerizes to a germanic bis‐heterocyclic product P3 via a transition state TS3 with energy barrier of 4.5 kJ/mol. The process of channel (B) is as follows: (1) the two reactants (R1, R2) first form an intermediate INT4 through a barrier‐free exothermic reaction of 251.5 kJ/mol; (2) INT4 further reacts with aldehyde (R2) to form an intermediate INT5, which is also a barrier‐free exothermic reaction of 173.5 kJ/mol; (3) INT5 then isomerizes to a germanic bis‐heterocyclic product P5 via a transition state TS5 with an energy barrier of 69.4 kJ/mol. © 2010 Wiley Periodicals, Inc. Int J Quantum Chem, 2011  相似文献   

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