Spin Squeezing and Entanglement of Many-Particle Spin-Half States

In many-particle spin-half systems with exchange symmetry, we find that the spin squeezing is related to two types of entanglement, the bipartite and the pairwise entanglement. A quantitative relationship is revealed for the spin squeezing parameter, the tangle, and the concurrence. We find that a class of states is spin squeezed if the pairwise entanglement is stronger than the bipartite entanglement.     

综合题新编选登

题 79　已知P ,Q是椭圆C :x2a2 + y2b2 =1(a >b >0 )上两个动点 ,O为原点 ,直线OP的斜率为k ,而直线OP与OQ的斜率之积为m ,且 p =|OP| 2 + |OQ| 2 是一个与k无关的定值 .1)求m ,p的值 ;2 )若双曲线Γ的焦点在x轴上 ,渐近线方程为y =±mx ,椭圆C与双曲线Γ的离心率分别为e1,e2 ,求e2 -e1的取值范围 .解　OP的方程为 :y =kx ,与椭圆C的方程联立 ,可得 :x2 =a2 b2b2 +a2 k2 ,∴ |OP| 2 =x2 + y2 =(1+k2 )x2=a2 b2 (1+k2 )b2 +a2 k2 .同理可求得 :|OQ| 2 =a2 b2 [1+ (mk) 2 ]b2 +a2 ·(mk) 2=(k2 +m2 )a2 b2a2 m2 +b2 k2 .∴ p =|OP| …     

High Power One- and Two-Order Cascaded Raman Lasers Based on Home-Made Phosphosilicate Fibre

One- and two-order cascaded Raman fibre lasers are demonstrated by using home-made P-doped Raman fibres.An output power of 2.8 W at 1245 nm with a slope efficiency of 33.4% and an output power of 2.0 W at 1495 nm with a slope efficiency of 23.5% are obtained with the pump source at 1069. 7nm.     

综合题新编选登

题167已知直三棱柱ABC-A1B1C1中有下列三个条件:①A1B⊥AC1;②A1B⊥B1C;③B1C1=A1C1.试利用①,②,③构造出一个你认为正确的命题,并加以证明.图1三棱柱解设C1A1=a,C1B1=b,C1C=c.A1B⊥AC1A1B·AC1=0(b-a c)(-a-c)=0-a·b a2-c2=0(1)A1B⊥B1CA1B·B1C=0(b-a c)(c-b)=0c2-b2 a·b=     

试题研讨(22)

试题(2004届第五次大联考试题)已知平面上一定点C(-1,0)和一定直线l:x=-4,P为该平面上一动点,作PQ( )l,垂足为Q, (PQ→ PC→)·(PQ→-2PC→)=0.     

平面上Volterra型随机微分方程解的轨道惟一性

In this paper we prove the pathwise uniqueness of a kind of two-parameter Volterra type stochastic differential equations under the coefficients satisfy the nonLipschitz conditions. We use a martingale formula in stead of Itǒ formula, which leads to simplicity the process of proof and extends the result to unbounded coefficients case.     

试题研讨 (12)

题 1　 (2 0 0 3年 3月湖北省黄石二中、黄冈中学、华师一附中等八校联考题 ,杨志明命题 )　已知函数 f(t)对任意实数x、y都有f(x+ y) =f(x) + f(y) + 3xy(x+y+ 2 )+ 3 ,f(1) =1.(1)若t为自然数 ,试求f(t)的表达式 ;(2 )满足条件 f(t) =t的所有整数t能否构成等差数列 ?若能构成等差数列 ,求出此数列 ;若不能构成等差数列 ,请说明理由 ;(3 )若t为自然数 ,且当t≥ 4时 ,f(t) ≥mt2 + (4m+ 1)t+ 3m恒成立 ,求m的最大值 .命题溯源　此题是受 2 0 0 2年北京市朝阳区第二次模拟试题第 2 2题的启发 ,笔者自编而成 .此题与 2 0 0 2年济南市 6月份高…     

应用马尔科夫状态转移链的作战航空综合体效能评估

文章阐述了作战航空综合体的相关概念及组成,应用马尔科夫状态转移链建立了作战航空综合体完成典型作战任务时的数学模型,确定了作战效能的评估指标,最后通过具体算例检验了模型的正确性和可行性.