首页 | 本学科首页   官方微博 | 高级检索  
     检索      


The best possibility of the grand Furuta inequality
Authors:  tarô  Tanahashi
Institution:Department of Mathematics, Tohoku College of Pharmacy, Komatsushima, Aoba-ku, Sendai 981-8558, Japan
Abstract:Let $ A, B \in B(H)$ be invertible bounded linear operators on a Hilbert space $H$ satisfying $O\leq B \leq A$ , and let $ p, r, s , t $ be real numbers satisfying $ 1 < s, 0 < t < 1 , t \leq r , 1 \leq p . $ Furuta showed that if $ 0 < \alpha \leq \dfrac{ 1-t+r}{ (p-t)s + r} $, then $ \left\{ A^{\frac{r}{2}} \left( A^{ -\frac{t}{2}} B^{p} A^{ -\frac{t}{2}} \right)^{s} A^{\frac{r}{2}} \right\}^{\alpha } \leq A^{ \left\{ (p-t)s + r \right\} \alpha } $. This inequality is called the grand Furuta inequality, which interpolates the Furuta inequality $(t=0)$
and the Ando-Hiai inequality ( $ t=1, r = s $ ).

In this paper, we show the grand Furuta inequality is best possible in the following sense: that is, if $ \dfrac{ 1-t+r}{ (p-t)s + r} < \alpha $, then there exist invertible matrices $A,B$ with $O\leq B \leq A$ which do not satisfy $ \left\{ A^{\frac{r}{2}} \left( A^{ -\frac{t}{2}} B^{p} A^{ -\frac{t}{2}} \right)^{s} A^{\frac{r}{2}} \right\}^{\alpha } \leq A^{ \left\{ (p-t)s + r \right\} \alpha } $.

Keywords:The L\"owner-Heinz inequality  the Furuta inequality  the grand Furuta inequality
点击此处可从《Proceedings of the American Mathematical Society》浏览原始摘要信息
点击此处可从《Proceedings of the American Mathematical Society》下载免费的PDF全文
设为首页 | 免责声明 | 关于勤云 | 加入收藏

Copyright©北京勤云科技发展有限公司  京ICP备09084417号