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Pyrolysis of dimethyl peroxide
Authors:L. Batt  R. D. McCulloch
Abstract:By using isobutane (t-BuH) as a radical trapit has been possible to study the initial step in the decomposition of dimethyl peroxide (DMP) over the temperature range of 110–140°C in a static system. For low concentrations of DMP (2.5 × 10?5?10?4M) and high pressures of t?BuH (~0.9 atm) the first-order homogeneous rate of formation of methanol (MeOH) is a direct measure of reaction (1): documentclass{article}pagestyle{empty}begin{document}${rm DMP}mathop to limits^1 2{rm Me}mathop {rm O}limits^{rm .},{rm Me}mathop {rm O}limits^{rm .} + t{rm - BuH}mathop to limits^4 {rm MeOH} + t{rm -}mathop {rm B}limits^{rm .} {rm u}$end{document}equation image. For complete decomposition of DMP in t-BuH, virtually all of the DMP is converted to MeOH. Thus DMP is a clean thermal source of Medocumentclass{article}pagestyle{empty}begin{document}$mathop {rm O}limits^{rm .}$end{document}equation image. In the decomposition of pure DMP complications arise due to the H-abstraction reactions of Medocumentclass{article}pagestyle{empty}begin{document}$mathop {rm O}limits^{rm .}$end{document}equation image from DMP and the product CH2O. The rate constant for reaction (1) is given by k1 = 1015.5?37.0/θ sec?1, very similar to other dialkyl peroxides. The thermochemistry leads to the result D(MeO? OMe) = 37.6 ± 0.2 kcal/mole and /Hurn:x-wiley:05388066:media:KIN550080403:tex2gif-stack-1(Medocumentclass{article}pagestyle{empty}begin{document}$mathop {rm O}limits^{rm .}$end{document}equation image) = 3.8 ± 0.2 kcal/mole. It is concluded that D(RO? OR) and D(RO? H) are unaffected by the nature of R. From ΔSurn:x-wiley:05388066:media:KIN550080403:tex2gif-stack-2 and A1, k2 is calculated to be 1010.3±0.5 M?1· sec?1: documentclass{article}pagestyle{empty}begin{document}$2{rm Me}mathop {rm O}limits^{rm .} mathop to limits^2 {rm DMP}$end{document}equation image. For complete reaction, trace amounts of t-BuOMe lead to the result k2 ~ 109 M?1 ·sec?1: documentclass{article}pagestyle{empty}begin{document}$2t{rm - Bu}mathop to limits^5$end{document}equation image products. From the relationship k6 = 2(k2k5a)1/2 and with k5a = 108.4 M?1 · sec?1, we arrive at the result k6 = 109.7 M?1 · sec?1: documentclass{article}pagestyle{empty}begin{document}$2t{rm - u}mathop {rm B}limits^{rm .} to (t{rm - Bu)}_{rm 2}{rm,}t{rm -}mathop {rm B}limits^{rm .} {rm u} + {rm Me}mathop {rm O}limits^{rm .} mathop to limits^6 t{rm - BuOMe}$end{document}equation image.
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