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Rhodium(III) and iridium(III) olefin complexes containing the tridentate ligand 1,6-bis(diphenylphosphino)-trans-hex-3-ene: crystal and molecular structure of trichloro-1,6-bis(diphenylphosphino)-trans-hex-3-eneiridium(III).
Authors:George R Clark  Peter W Clark  Karen Marsden
Institution:1. Department of Chemistry, University of Auckland, Private Bag, Auckland Auckland New Zealand;2. Department of Chemistry, University of Queensland, Brisbane 4067, Queensland Australia
Abstract:The olefin complexes RhCl3(BDPH), RhClBr2(BDPH), IrCl3(BDPH), IrClBr2(BDPH), IrCl(CH3)I(BDPH), IrHCl2(BDPH) and IrHBr2(BDPH); BDPH = 1,6-bis(diphenylphosphino)-trans-hex-3-ene, have been prepared by oxidative-addition reactions of RhCl(BDPH) and IrCl(BDPH) and characterised by I.R. and 1H NMR spectra. A single crystal X-ray determination of the structure of IrCl3(BDPH) shows the crystals to be orthorhombic, a = 16.1636(13), b = 20.2927(7), c = 17.1916(6)Å, Z = 8, space group Pbca, ?obs = 1.76, ?calc = 1.77 g cm?3. The structure was solved by conventional methods and refined by use of full-matrix least-squares equations to final residuals R = 0.041 and Rw = 0.052 for 2926 observed reflections.The complex is monomeric with an octahedral coordination geometry consisting of the tridentate olefin(phosphine)2 BDPH ligand (arranged such that the phosphorus atoms are mutually trans, and the three chloride ligands. Distances observed are Ir-P 2.382, 2.389(2)Å, Ir-Cl 2.358, 2.387 (trans to olefin), 2.371(2)Å, Ir-C(olefin) 2.274, 2.277(10)Åf, C=C 1.352(14)Å. The olefin is inclined at an angle of 28° to the Ir, P(1), P(2), Cl(2) plane. The structure is compared and contrasted with the known structures of IrCl(BDPH) and IrH2Cl(BDPH).
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