摘 要: | §1.(?)=f(t,x)的周期解考虑一般情形(?)=f(t,x),x∈R~n,(1.1)其中 f(t,x)是连续的以ω为周期的周期函数.引入下列记号:B_ω={u(t);u(t)∈C_([0,ω]),u(0)=u(ω)}‖u‖=(?)|u(t)|,对 u(t)∈B_ω.则 B_ω为一 Banach 空间.再记B_1={u(t);u(t)∈B_ω,且对任意 t∈[0,ω] u(t)=u(0)},B_2={u(t);u(t)∈B_ω,且 integral from n=0 to ω u(t)dt=0},则 B_1∩B_2={0}.B_ω有直和分解 B_ω=B_1(?)B_2,且
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