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关于指数丢番图方程a2x+(3a2-1)y=(4a2-1)z
引用本文:胡永忠. 关于指数丢番图方程a2x+(3a2-1)y=(4a2-1)z[J]. 数学进展, 2007, 36(4): 429-434
作者姓名:胡永忠
作者单位:中南大学数学科学与计算技术学院,长沙,湖南,410075;佛山科学技术学院数学系,佛山,广东,528000
摘    要:设a>3是一个整数,应用Bilu,Hanrot和Voutier关于本原素除子的深刻理论以及二次数域类数的一些结果,证明了指数丢番图方程a2x+(3a2-1)y=(4a2-1)z仅有正整数解x=y=1.

关 键 词:指数丢番图方程  Lucas序列  本原素除子  Kronecker(Legendre)符号
文章编号:1000-0917(2007)04-0429-06
修稿时间:2005-06-16

On the Exponential Diophantine Equation a2x+(3a2-1)y=(4a2-1)z
HU Yongzhong. On the Exponential Diophantine Equation a2x+(3a2-1)y=(4a2-1)z[J]. Advances in Mathematics(China), 2007, 36(4): 429-434
Authors:HU Yongzhong
Affiliation:School of Mathematical Sciences and Computing Technology Central South University, Changsha, Hunan, 410075, P. R. China;Department of Mathematics, Foshan University, Foshan, Guangdong, 528000, P.R. China;Department of Mathematics, Foshan University, Fosha
Abstract:Let a > 3 be an integer, we apply a new, deep theorem of Bilu, Hanrot & Voutier and some results on the class number of quadratic field to show that the only positive integer solution of the exponential Diophantine equation a2x+(3a2-1)y=(4a2-1)z is x = y = z = 1.
Keywords:exponential Diophantine equations  Lucas sequences  primitive divisors  Kronecker(Legendre) symbol
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