Precise excitation energy and γ-ray decay of the lowest T = 2 state in 40K

The excitation energy of the lowest T = 2 state in ⁴⁰K has been determined as E_x = 4384.0 ± 0.3 keV from n-γ and γ-γ coincidence experiments. The state was populated with the ⁴Ar(p,n)⁴⁰K reaction at E_p = 8.30 MeV. Gamma-gamma angular correlation measurements yield unambiguous spin assignments J = 0 and 1 for the 1.64 and 2.290 MeV states, respectively. The excitation energy of the T = 2, J^π = 0⁺ state leads to a calculated mass excess of ?9120 ± 150 keV for ⁴⁰Ti.