Redox reactions of uranium hexafluoride. Comparison with phosphorus pentafluoride and preparation of copper(I) hexafluorouranate(V) [1] |
| |
| Authors: | Dilip K Sanyal David WA Sharp John M Winfield |
| |
| Institution: | Department of Chemistry, University of Glasgow, Glasgow, G12 8QQ, U.K. |
| |
| Abstract: | Molecular iodine is oxidised by phosphorus pentafluoride in iodine pentafluoride at room temperature giving I2+, PF6?, and PF3. I2+ is formed from uranium hexafluoride under similar conditions, but further oxidation occurs depending on the reaction stoicheiometry used. In all cases uranium pentafluoride is formed. Copper(II) fluoride reacts with UF5 in acetonitrile at room temperature to give copper(II) hexafluorouranate(V), which is reduced by copper metal to give the copper(I) salt. The latter compound is formed from UF6 and Cu metal, via the CuII salt, only if a fresh Cu surface is used for the reduction step. |
| |
| Keywords: | |
| 本文献已被 ScienceDirect 等数据库收录！ |
|
