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Degrees of difficulty of generalized r.e. separating classes
Authors:Douglas Cenzer  Peter G. Hinman
Affiliation:(1) Department of Mathematics, University of Florida, 358 Little Hall, PO Box 118105, Gainesville, FL 32611-8105, USA;(2) Department of Mathematics, University of Michigan, Ann Arbor, MI, USA
Abstract:Important examples of $$Pi^0_1$$ classes of functions $$f in {}^omegaomega$$ are the classes of sets (elements of ω 2) which separate a given pair of disjoint r.e. sets: $${mathsf S}_2(A_0, A_1) := {f in{}^omega2 : (forall i < 2)(forall x in A_i)f(x) neq i}$$. A wider class consists of the classes of functions f ω k which in a generalized sense separate a k-tuple of r.e. sets (not necessarily pairwise disjoint) for each kω: $${mathsf S}_k(A_0,ldots,A_k-1) := {f in {}^omega k : (forall i < k) (forall x in A_i) f(x) neq i}$$ . We study the structure of the Medvedev degrees of such classes and show that the set of degrees realized depends strongly on both k and the extent to which the r.e. sets intersect. Let $${mathcal S}^m_k$$ denote the Medvedev degrees of those $${mathsf S}_k(A_0,ldots,A_{k-1})$$ such that no m + 1 sets among A 0,...,A k-1 have a nonempty intersection. It is shown that each $${mathcal S}^m_k$$ is an upper semi-lattice but not a lattice. The degree of the set of k-ary diagonally nonrecursive functions $$mathsf{DNR}_k$$ is the greatest element of $${mathcal S}^1_k$$ . If 2 ≤ l < k, then 0 M is the only degree in $${mathcal S}^1_l$$ which is below a member of $${mathcal S}^1_k$$ . Each $${mathcal S}^m_k$$ is densely ordered and has the splitting property and the same holds for the lattice $${mathcal L}^m_k$$ it generates. The elements of $${mathcal S}^m_k$$ are exactly the joins of elements of $${mathcal S}^1_i$$ for $$lceil{k over m}rceil leq i leq k$$ . Supported by National Science Foundation grants DMS 0554841, 0532644 and 0652732.
Keywords:Medvedev reducibility  Degrees  Separating class
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