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Bezout Rings,Polynomials, and Distributivity
Authors:Tuganbaev  A A
Institution:(1) Moscow Power Engineering Institute, Russia
Abstract:Let A be a ring, phiv be an injective endomorphism of A, and let 
$$A_r \left {x,\varphi } \right] \equiv R$$
be the right skew polynomial ring. If all right annihilator ideals of A are ideals, then R is a right Bezout ring 
$$ \Leftrightarrow A$$
is a right Rickartian right Bezout ring, phiv(e)=e for every central idempotent eisinA, and the element phiv(a) is invertible in A for every regular aisinA. If A is strongly regular and nge 2, then R/x n R is a right Bezout ring 
$$ \Leftrightarrow $$
R/x n R is a right distributive ring 
$$ \Leftrightarrow $$
R/x n R is a right invariant ring 
$$ \Leftrightarrow $$
phiv(e)=e for every central idempotent eisinA. The ring R/x 2 R is right distributive 
$$ \Leftrightarrow $$
R/x n R is right distributive for every positive integer n 
$$ \Leftrightarrow $$
A is right or left Rickartian and right distributive, phiv(e)=e for every central idempotent eisinA and the phiv(a) is invertible in A for every regular aisinA. If A is a ring which is a finitely generated module over its center, then Ax] is a right Bezout ring 
$$ \Leftrightarrow $$
Ax]/x 2 Ax] is a right Bezout ring 
$$ \Leftrightarrow $$
A is a regular ring.
Keywords:skew polynomial ring  Bezout ring  distributive ring
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