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Prime Producing Quadratic Polynomials and Class Number One or Two
Authors:Email author" target="_blank">Anitha?SrinivasanEmail author
Institution:(1) Departamento de Matematicas, Universidad de Puerto-Rico, Humacao, Puerto Rico, 00791;(2) Present address: Department of Mathematics, Indian Institute of Technology, Powai, Mumbai, India, 400 076
Abstract:Let d≡ 5 mod 8 be a positive square-free integer and let h(d) be the class number of the real quadratic field ℚ(√d). Let p be a divisor of d = pq and let $$f_p(x)=\vert p{x}^{2} + px + \frac{p-q}{4}\vert$$ . Assume that $$f_p(x)$$ is prime or equal to 1 for all integers x with 0≤x<W. Under the assumption that the Riemann hypothesis is true, we prove that if $$W=\frac{1}{2}(\sqrt{\frac{d}{5}}-1)$$ , then h(d) < 2. Furthermore we show that h(d)< 2 implies d < 4245. In the case when there exists at least one split prime less than W, we prove the following results without any assumptions on the Riemann hypothesis. If $$W=\frac{\sqrt{d}}{4}-\frac{1}{2}$$ then h< 2 or h = 4. If $$W=\frac{1}{2}(\sqrt{\frac{d}{5}}-1)$$ , then h≤ 2, h = 4 or h = 2t−2, where t is the number of primes dividing d. In the case when h = 2t−2 we have $$d=p^{2}\phi^{2}\pm p$$ , where φ = 2 or 4. 2000 Mathematics Subject Classification: Primary–11R29
Keywords:class number  binary quadratic forms  quadratic field  prime producing polynomials
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