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关于树的代数连通度的Fiedler不等式的新证明
引用本文:范益政. 关于树的代数连通度的Fiedler不等式的新证明[J]. 数学研究, 2003, 36(4): 379-383
作者姓名:范益政
作者单位:南京师范大学数学系,江苏,南京,210097;安徽大学数学系,安徽,合肥,230039
基金项目:The project item of scientific research support for youth teachers of colleges and universities of Anhui province(2003jq101)
摘    要:设T为含n个顶点的树,L(T)为其Laplace矩阵,L(T)的次小特征值α(T)称为T的代数连通度,Fiedlcr给出如下关于α(T)的界的经典结论α(Pn)≤α(T)≤α(Sn),其中Pn,Sn分别为含有n个顶点的路和星.Merris和Mass独立地证明了:α(T)=α(Sn)当且仅当T=Sn.通过重新组合由Fiedler向量所赋予的顶点的值,本给出上述不等式的新证明,并证明了:α(T)=α(Pn)当且仅当T=Pn。

关 键 词:树 Laplace矩阵 代数连通度

A New Proof of Fiedler′s Inequality on the Algebraic Connectivity of Trees
Abstract. A New Proof of Fiedler′s Inequality on the Algebraic Connectivity of Trees[J]. Journal of Mathematical Study, 2003, 36(4): 379-383
Authors:Abstract
Abstract:Let T be a tree on n vertices and let L(T) be the Laplacian matrix of T. The second smallest eigenvalue u(T) of L(T) is called the algebraic connectivity of T. A classical result on the bounds for a(T) is given by Fielder [1] as follows:where Pn and Sn denote respectively the path and the star on n vertices. In [9] and [8], Merris and Mass proved independently that a(T)=a(Sn) if and only if T=Sn In this paper, by recombining the valuation of the vertices which are given by a Fiedler vector (the eigenvector of L(T) corresponding to a(T)), we provide a new proof of above inequality, and also show that a(T) = a(Pn) if and only if T =Pn.
Keywords:Tree  Laplacian matrix  algebraic connectivity
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