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Localizations of Transfors
Authors:Sjoerd E Crans
Institution:(1) School of Mathematics, Physics, Computing and Electronics, Macquarie University, NSW, 2109, Australia;(2) Present address: Institut de Recherche Mathématique Avancée, Université Louis Pasteur, 7 rue René-Descartes, 67084 Strasbourg, France
Abstract:Let 
$$\mathbb{C}{\text{, }}\mathbb{D} {\text{and }}\mathbb{E}$$
be n-dimensional teisi, i.e., higher-dimensional Gray-categorical structures. The following questions can be asked. Does a left q-transfor 
$$\mathbb{C} \to \mathbb{D}$$
, i.e., a functor 2 q 
$$ \otimes {\text{ }}\mathbb{C} \to \mathbb{D}$$
, induce a right q-transfor 
$$\mathbb{C} \to \mathbb{D}$$
, i.e., a functor 
$$\mathbb{C} \otimes {\text{ 2}}q \to \mathbb{D}{\text{?}}$$
More generally, does a functor 
$$\mathbb{C} \otimes {\text{ }}\mathbb{D} \to \mathbb{E}$$
induce a functor 
$$\mathbb{C} \otimes {\text{ }}\mathbb{D} \to \mathbb{E}{\text{?}}$$
For k-arrows c and 
$$c' \in \mathbb{C}$$
whose (k – 1)-sources and targets agree, does a q-transfor 
$$\mathbb{C} \to \mathbb{D}$$
induce a q-transfor 
$$\mathbb{C}(c,c') \to \mathbb{D}(d,d')$$
, for appropriate k-arrows 
$$d{\text{ and }}d' \in \mathbb{D}{\text{?}}$$
For k-arrows c and 
$$c' \in \mathbb{C}{\text{ and }}d{\text{ and }}d' \in \mathbb{D}$$
whose (k – 1)-sources and targets agree, does a q-transfor 
$$\mathbb{C} \otimes {\text{ }}\mathbb{D} \to \mathbb{E}$$
induce a (q + k + 1)-transfor 
$$\mathbb{C}(c,c') \otimes \mathbb{D}(d,d') \to \mathbb{E}(e,e')$$
, for appropriate k-arrows 
$$e{\text{ and }}e' \in \mathbb{E}{\text{?}}$$
I give answers to these questions in the cases where n-dimensional teisi and their tensor product have been defined, i.e., for n le 3, and for n up to 5 in some cases that do not need all data and axioms of n-dimensional teisi.I apply the above to compositions in teisi, in particular to braidings and syllepses. One of the results is that a braiding on a monoidal 2-category induces a pseudo-natural transformation 
$$\widetilde{{\text{?}} \otimes - } \to {\text{?}} \otimes - $$
, where 
$$\widetilde{{\text{?}} \otimes - }$$
is the lsquoreversersquo of ? otimes –, which is almost, but not quite, equal to – otimes ?. However, in higher dimensions otimes need not be reversible, so a braiding on a higher-dimensional tas can not be seen as a transfor A otimes B rarr B otimes A.
Keywords:braiding  natural transformation  Gray-category  symmetry  tas  transfor
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