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Crystal structure of PbUO2(CH3COO)4(H2O)3
Authors:L. B. Serezhkina   A. V. Vologzhanina   V. V. Klepov  V. N. Serezhkin
Abstract:Single crystals of PbUO2(CH3COO)4(H2O)3 have been investigated by X-ray diffraction (R = 0.029 for 3175 reflections). The structure of this compound is formed by [Pb(CH3COO)(H2O)3]+ chains, which are oriented along the [100] axis and limited by one-core complexes [UO2(CH3COO)3]. The coordination numbers of the Pb(II) and U(VI) atoms are 8, and the coordination polyhedron of uranium is a hexagonal bipyramid whose vertices contain oxygen atoms of three bidentate cyclic acetate groups and the uranyl group. Taking into account the different crystallographic roles of acetate ions, the crystal-chemical formula of [PbUO2(CH3COO)4(H2O)3] chains can be written as AAB 21 B 11(B 01)2 M 31, where A = Pb; A′ = UO22+; M 1 = H2O; and B 21, B 11, and B 01 are CH3COO groups.
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