Crystal structure of (5-methylcyclopentadienyl)-(1,5-cyclooctadiene) iridium(I) |
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Authors: | K V Zherikova N B Morozova and I A Baidina |
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Institution: | (1) A. V. Nikolaev Institute of Inorganic Chemistry, Siberian Division, Russian Academy of Sciences, Novosibirsk, Russia |
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Abstract: | XRD is used to determine the structure of Cp′Ir(cod) at a temperature of 150(2) K. Crystallographic data for C14H19Ir are: a = 10.8272(5) ?, b = 9.7746(4) ?, c = 10.9180(5) ?, β = 97.3310(10)°, monoclinic symmetry, space group P21/n, V = 1146.02(9) ?3, Z = 4, d
calc= 2.199 g/cm3, R = 0.0246. The structure is molecular, built of neutral molecules. The metal atom coordinates carbon atoms of two cyclic ligands:
5-methylcyclopentadienyl-ion (Cp′) and 1,5-cyclooctadiene (cod). Five Ir-CCp′ distances lie in the range of 2.21–2.28 ?; four Ir-Ccod distances differ insignificantly, and their average value is 2.114(13) ?. The C11C12C13C14C15 and C1C2C5C6 planes of ligand fragments are almost parallel, and the angle between normals is 1.9°. In the crystal, molecules are bonded
only by van der Waals interactions; in the structure, the eight shortest Ir...Ir distances are in the range of 5.608–7.257
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Original Russian Text Copyright ? 2009 by K. V. Zherikova, N. B. Morozova, and I. A. Baidina
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Translated from Zhurnal Strukturnoi Khimii, Vol. 50, No. 3, pp. 591–594, May–June, 2009. |
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Keywords: | iridium(I) 1 5-cyclooctadiene 5-methylcyclopentadiene synthesis X-ray diffraction analysis |
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