二苯乙醇酸铜配合物的合成、晶体结构、电化学和荧光性质

以二苯乙醇酸为配体合成了1个新的化合物Cu(2,2′-bipy)(BAA)]Cu(2,2′-bipy)(BAA)(H2O)]2.(H2O)3(BAA=二苯乙醇酸阴离子,2,2′-bipy=2,2′-联吡啶)。该化合物晶体属三斜晶系,空间群P1,晶胞参数:a=1.121 7(5)nm,b=1.360 2(6)nm,c=2.335 2(10)nm,α=99.260(6)°,β=101.223(8)°,γ=94.805(8)°,V=3.425(3)nm3,Dc=1.385 g.cm-3,Z=6,μ(Mo Kα)=0.992 mm-1,F(000)=1 474,最终偏离因子R1=0.0561,wR2=0.1128。在标题化合物的不对称单元中有3个单核铜(Ⅱ)配合物,且3个中心铜(Ⅱ)离子的配位数不完全相同,如Cu(1)离子的配位数是4,而Cu(2)和Cu(3)离子的配位数都是5。本文还测定了标题化合物的电化学性能和荧光性能,结果表明:在电化学过程中配合物的电子转移是准可逆的,电子转移数为2个;配合物在478 nm的光激发下可发射荧光。

Synthesis, Crystal Structure, Electrochemical and Luminescent Properties of a Copper(H) Complex with Benzilic Acid as Ligand

A complex Cu(2,2'-bipy)( BAA)]Cu(2,2'-bipy)( BAA)(H2O)]2·(H2O)3 (BAA=benzilic acid anion,2,2'-bipy=2,2'-bipyridine) has been synthesized.Crystal data for this complex are as follows:triclinic,space group P(1),a=1.121 7(5) nm,b=1.360 2(6) nm,c=2.335 2(10) nm,α=99.260(6)°,β=101.223(8)°,γ=94.805(8)°,V=3.425(3) nm3,Dc=1.385 g·cm-3,Z=6,μ(Mo Kα)＝0.992 nm-1,F(000)=1 474,final discrepancy factors R1＝0.056 1,wR2＝O.112 8.There are three mononuclear copper(Ⅱ) complexes in one asymmetric unit of the compound,where the three central Cu(Ⅱ) ions are not all of the same coordination number.Cu(1) ion is tetra-coordinated,while Cu(2) ion and Cu(3) ion are both penta-coordinated.The cyclic voltammetric behavior and fluorescent property of the title compound were investigated.The results show that the electron transfer in the electrode reaction of the title complex is irreversible,and two electrons are involved in the oxidation of the title complex.When the exciting radiation setting at 478 nm,the title complex can give off fluorescent emission.CCDC:788067.