On the Diophantine equations $$z^2=f(x)^2 \pm f(y)^2$$ z 2 = f ( x ) 2 ± f ( y ) 2 involving quartic polynomials 期刊界 All Journals 搜尽天下杂志传播学术成果专业期刊搜索期刊信息化学术搜索

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On the Diophantine equations $$z^2=f(x)^2 \pm f(y)^2$$ z 2 = f ( x ) 2 ± f ( y ) 2 involving quartic polynomials

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