Abstract: | Reaction of tetraphosphine complex Mo(κ4‐P4)(Ph2PCH2CH2PPh2)] (1; P4 = meso‐o‐C6H4‐(PPhCH2CH2PPh2)2) with E‐1,3‐pentadiene in toluene at 60 °C gave the η4‐diene complex Mo(η4‐E‐1,3‐pentadiene)(κ4‐P4)] (2), which is present as a mixture of two isomers due to the orientation of the Me group in the diene ligand. Treatment of 1 with Z‐1,3‐pentadien also resulted in the formation of 2 as the sole product after heating the reaction mixture at 90 °C. Whereas the reaction of 1 with 1,3‐cyclohexadiene at 60 °C afforded the η4‐diene complex Mo(η4‐cyclohexadiene)(κ4‐P4)] (6), that with cyclopentadiene led to the C‐H bond scission product η5‐C5H5)MoH(κ3‐P4)] (7). Detailed structures were determined by X‐ray crystallography for 2, 6,and 7, and fluxional feature of 6 in solution was clarified based on the VT‐NMR studies. |