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101.
102.
103.
本文设计并研制了一种实用型三谱段太阳模拟器,其光谱匹配可同时调整3个谱段(300~700 nm,700~900 nm,900~1 700 nm)范围的能量,修正后可满足三结砷化镓太阳电池的测试使用要求。本文重点阐述了三谱段太阳模拟器滤光片的设计和氙灯光谱的修正及测试,介绍了太阳模拟器的光机结构。实验表明:三谱段太阳模拟器的光谱匹配满足三结砷化镓太阳电池各子电池的响应电流值。在有效辐照面150 mm×150 mm上,平均辐照度可以达到2个太阳常数(2 730 W/m2),辐照不均匀度达到±1.77%,辐照不稳定度达到±0.83%,为太阳电池自动分拣系统提供了可靠稳定的平台。 相似文献
104.
In this note we present a new proof of the quintuple product identity which is based on our study of order theta functions with characteristics and the identities they satisfy. In this context the quintuple product identity is another example of an identity which when phrased in terms of theta functions, rather than infinite products and sums, has a simpler form and is much less mysterious.
105.
106.
It is well known that there is a planar sloop of cardinality n for each n≡2 or 4 (mod 6) (Math. Z. 111 (1969) 289–300). A semi-planar sloop is a simple sloop in which each triangle either generates the whole sloop or the 8-element sloop. In fact, Quackenbush (Canad. J. Math. 28 (1976) 1187–1198) has stated that there should be such semi-planar sloops. In this paper, we construct a semi-planar sloop of cardinality 2n for each n≡2 or 4 (mod 6). Consequently, we may say that there is a semi-planar sloop that is not planar of cardinality m for each m>16 and m≡4 or 8 (mod 12). Moreover, Quackenbush (Canad. J. Math. 28 (1976) 1187–1198) has proved that each finite simple planar sloop generates a variety, which covers the smallest non-trivial subvariety (the variety of all Boolean sloops) of the lattice of the subvarieties of all sloops. Similarly, it is easy to show that each finite semi-planar sloop generates another variety, which also covers the variety of all Boolean sloops. Furthermore, for any finite simple sloop
of cardinality n, the author (Beiträge Algebra Geom. 43 (2) (2002) 325–331) has constructed a subdirectly irreducible sloop
of cardinality 2n and containing
as the only proper normal subsloop. Accordingly, if
is a semi-planar sloop, then the variety
generated by
properly contains the subvariety
. 相似文献
107.
一个Mendelsohn三元系MTS(υ,λ)=(X,B)被称作是自反的,如果它与它的逆(X,B-1)是同构的,其中B-1={〈z,y,x〉;〈x,y,z〉∈B.在[2]中已给出了简单自反MTS((υ,1)的存在谱,即υ≡0,1(mod3),υ3且υ≠6.本文讨论一般λ的情况,并得到简单自反MTS(υ,λ)的存在谱是λυ(υ-1)≡0(mod3);λυ-2,υ3且(υ,λ)≠(6,1);(6,3). 相似文献
108.
Shin Satoh 《Proceedings of the American Mathematical Society》2005,133(2):613-616
Any surface-knot in 4-space can be projected into 3-space with a finite number of triple points, and its triple point number, , is defined similarly to the crossing number of a classical knot. By definition, we have for the connected sum. In this paper, we give infinitely many pairs of surface-knots for which this equality does not hold.
109.
We define symmetric spaces in arbitrary dimension and over arbitrary non-discrete topological fields
, and we construct manifolds and symmetric spaces associated to topological continuous quasi-inverse Jordan pairs and -triple systems. This class of spaces, called smooth generalized projective geometries, generalizes the well-known (finite or infinite-dimensional) bounded symmetric domains as well as their ‘compact-like’ duals. An interpretation of such geometries as models of Quantum Mechanics is proposed, and particular attention is paid to geometries that might be considered as ‘standard models’ – they are associated to associative continuous inverse algebras and to Jordan algebras of hermitian elements in such an algebra.Mathematics Subject Classiffications (2000). primary: 17C36, 46H70, 17C65; secondary:
17C30, 17C90 相似文献
110.
Peter Danziger Peter Dukes Terry Griggs Eric Mendelsohn 《Graphs and Combinatorics》2006,22(3):311-329
A Steiner triple system of order v, or STS(v), is a pair (V, ) with V a set of v points and a set of 3-subsets of V called blocks or triples, such that every pair of distinct elements of V occurs in exactly one triple. The intersection problem for STS is to determine the possible numbers of blocks common to two Steiner triple systems STS(u), (U, ), and STS(v), (V, ), with U⊆V. The case where U=V was solved by Lindner and Rosa in 1975. Here, we let U⊂V and completely solve this question for v−u=2,4 and for v≥2u−3.
supported by NSERC research grant #OGP0170220.
supported by NSERC postdoctoral fellowship.
supported by NSERC research grant #OGP007621. 相似文献