从(n 1)/n×(n 1)=(n 1)/n (n 1)谈起

一问题的提出本刊2003年第5期刊载了《运用发现法解题》(以下简称《解题》)一文,文章在谈到“归纳发现法”时,提到这样一个例子: 1.观察下列各式     

n~(n 1)与(n 1)~n谁大?

学生曾问我“20022003与20032002谁大?”,他钻研后认为n(n 1)与(n 1)n(n∈N)当n取较小的值时,有时前者比后者小,有时前者比后者大,当n取较大的值时,又不好证明,这引起了我们的研究兴趣。     

sin(1/n)与cos(1/n)的无理性

当。是非零整数时,。i。卫是无理数。肛.根据sinx的慕极数展开式“无一(一1)友一眯汁而(会)’“’- 一蔺愉(:)2k ’十…〕·5 In犷二二二一生二。十主护一3!5!将(1)式两端同乘(2友 r)!nZ走 i得 (一1)*二产车一二,‘ ‘ … 又‘尺十1)!〔2“ ,):n,““S‘n令一‘*‘2* l):nZ“·‘ 左无(2畏 z)!。2左 1.(2)二I之 刃左,其中(l)显然上式右端第一境是整数,而第二项的艳对值为 IR,(2天 1)!。2‘ ‘l、一告- (一六幼31)无蔽 奥仁、,_…一(2左十‘”·2“’l石万十不件)2“‘3共节仁、,反 ,十lj刃\刀/ l/1\2毛 51一7二犷-,一丁二吸一1十…l 仁…     

巧用1/(n(n k))=1/k((1/n)-(1/(n k)))解竞赛题

一、用来解方程例1(1999年河北省竞赛题)方程1/(x(x-1)) 1/(x(x 1)) … 1/((x 1997)(x 1998)) =(1999)/(2000)的根为()．(A)1999 (B)-2 (C)-1999或2 (D)1999或-2解根据公式原方程化为1/(x-1)-1/x 1/x-1/(x 1) … 1/(1/(x 1997))-1/(x 1998)=(1999)/(2000),1/(x-1)-1/(x 1998)=(1999)/(2000),(x 1998)-(x-1)=(1999)/(2000)(x-1)(x 1998),1999=(1999)/(2000)(x-1)(x 1998),     

级数∞∑n=1nαsin(nβ)的收敛性

通过推导给出了使级数∞∑n=1nαsin(nβ)收敛的α与β的值.     

关于Lnz~(1/n)与(1/n)Lnz是否相等的讨论

对复变量z的函数Lnz~(1/n)与(1/n)Lnz的关系进行研究,发现Lnz~(1/n)与(1/n)Lnz,并给出证明,纠正"Lnz~(1/n)与(1/n)Lnz是两个不同函数"的错误认识.     

On the recursive sequencex n +1=α-(x n /x n −1)

We study the global asymptotic stability, global attractivity, boundedness character, and periodic nature of all positive solutions and all negative solutions of the difference equation $$x_{n + 1} = \alpha - \frac{{x_n }}{{x_{n - 1} }}, n = 0,1,...,$$ where α∈R is a real number, and the initial conditionsx?1,x ₀ are arbitrary real numbers.     

On the Congruence σ(n)≡1(mod n)

Let k≥2 be an integer,and let σ(n) denote the sum of the positive divisors of an integer n.We call n a quasi-multiperfect number if σ(n)=kn+1.In this paper,we give some necessary properties of them.     

More on the Difference Equation y n + 1 = ( p + y n −1 )/( qy n + y n −1 )

From previous studies of the equation in the title with positive parameters p and q and positive initial conditions we know that if q h 4 p + 1 then the equilibrium is a global attractor. We also know that if q > 4 p + 1 then every solution eventually enters and remains in the interval [ p / q , 1]. In this strip there exists a "unique" prime period two solution that is locally asymptotically stable. In this paper, we provide more insight as to the behavior of solutions of the equation in the title in the strip [ p / q , 1], where a one-dimensional stable manifold lives.     

Stable constant mean curvature hypersurfaces in ℝ n+1 and ℍ n+1(−1)

In this paper, we show that all complete stable hypersurfaces in ⁿ⁺¹(or ⁿ⁺¹ (-1)) (n = 3, 4, 5) with constant mean curvature H > 0 (or H > 1, respectively) and finite L ² norm of traceless second fundamental form are compact geodesic spheres. Keywords: stable hypersurface, constant mean curvature, isometric immersion, Bernstein theorem.*Supported by PolyU grant G-T575.**Partially supported by CNPq of Brazil.     

Répartitio n simulta née de S( n) et $$ S( n+1)$$ S( n+1) da ns les progressio ns arithmétiques

If \(q\ge 2\) is an integer, we denote by \(S_q(n)\) the sum of the digits in base q of the positive integer n and by \(v_q(n)\) its q-adic valuation. The goal of this work is to study exponential sums of the form \(\displaystyle \sum \nolimits _{n\le x}\exp \big (2i\pi \big (\frac{l}{m} S_q(n)+\frac{k}{m'}S_q(n+1)+\theta n\big )\big )\) in order to prove some statistical properties of integers n for which \(S_q(n)\) and \(S_q(n+1)\) belong to given arithmetic progressions. This extends the results obtained by Gelfond in 1968 and those obtained by Mauduit–Sárközy in 1996.     

求sun from n=1 to ∞ (1/n) K~2与sun from n=1 to ∞ (1/n) K~3的两种简单方法

几何法(l)求艺k: 含.!令k二l,2,3、…,n.对每一个k的位,作如图l所示的边一长为介的正方形4个,如图2所示的边长分别为1,无艺的矩形2个。技图3所示方式,将它们排列成涡形状。于是所有这些小块方形,拼成了一个如图3所示的矩形(利用数学归纳法,读者不难证lljl)。 丫对每一个k的值,所作6个小块方形而积之和为6k2,┌──┐│寿名│└──┘:.所拼矩形的面积二6艺k,11下卜一尸一一一叫已二立二习图2 另一方面,由图3一可知,这个矩形的长为如十卜宽为。’+,二。(。十l),所以又有 所拼矩j卜的面积=n(n+l)(Zn+l)。从而有6艺k艺=,,(“+1)(2,,+1) 山1┌…     

重要极限limn→∞(1+1/n)n存在性的简洁证法

利用均值不等式(n∏i=1ai)1/n≤1/nn∑i=1ai给出了重要极限limn→∞(1 1/n)n存在性的一种简洁证明方法,特别是数列{(1 1/n)n}的有界性的证明非常简洁.同时给出了均值不等式的一种初等证法.     

On positive integers n with $$\sigma _l (2n+1)<\sigma _l (2n)$$ σ l ( 2 n + 1 ) < σ l ( 2 n )

Periodica Mathematica Hungarica - For any integer l and any positive integer n, let $$ \sigma _{l}(n)=\sum _{d\mid n}d^{l}$$ . In 1936, Erd?s proved that the set of positive integers n with...     

数列{((n!)~(1/n))/n)}极限的简便求法

给出了数列{((n!)~(1/n))/n)}的极限的一种简便求法     

数列{n/(n!)~(1/n)}极限的教学价值

给出数列{n/(n!)~(1/n)}极限的八种灵活新颖的求解方法,进一步讨论了它的教学价值.     

lim(n→∞) sum from i=1 to n g(,n)的讨论

<正> 关于的计算问题,通常采用夹心法及化为定积分来计算。为对此类极限进行探讨,我们以如下特例考虑: