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1.
Quasi-Affinity in certain Classes of Operators   总被引:1,自引:0,他引:1  
The family of operators S + V (, C, Re > 0), where V isan injective S-Volterra operator (that is, [S, V[ = V2) and— AV–1 generates a uniformly bounded C0-semigroup,is studied in the context of similarity and of the weaker quasi-affinityrelation. It is shown that S is similar to S + V for all , C,Re > 1, and is a quasi-affine transform of S + tV for allt 0 and 0 < < 1.  相似文献   

2.
Professor W. F. Hammond has kindly drawn my attention to a blunderin 4 of the above paper. He referred to the ( – 2r) xß submatrix D of the skew-symmetric matrix displayednear the top of page 181, of which it is asserted that it issquare and non-singular, and pointed out that, from the factthat the matrix of which D forms part is regular, it may onlybe deduced that the columns of D are linearly independent; thatis, it only follows that – 2r ß. The validity of the equation – 2r = ß is essentialto the succeeding argument and, fortunately, may be establishedby alternative means. Using the nomenclature of the paper, wehave on F the set 1*, ..., 2r*, 1*, ..., ß* of independent3-cycles (independent because they cut independent 1-cycleson the curve C), which may be completed, to form a basis forsuch cycles on F, by a further set 1', ..., 2q–2r–pof independent 3-cycles, each of which meets C in a cycle homologousto zero on C. The cycles 1*, ..., * are invariant cycles andare independent on F so that, if > 2r + ß, thereis a non-trivial linear combination * of these having zero intersectionon C with each of the cycles 1*, ..., 2r*, 1*, ..., ß*.Thus we have. (* .k*)c = 0 = (* .i*)c i.e. (* .k*) = 0 = (* .i* on F (1 k 2r; 1 i ß). Furthermore, (j . C) 0 on C and we have (* .j .C)C = 0 i.e. (* .j) = 0 on F (1 j 2q – 2r – ß). It now follows that * 0 on F (for it has zero intersectionwith every member of a basic set of 3-cycles on F). But thiscondradicts the assumption that * is a non-trivial linear combinationof the independent cycles 1*, ...,*; and hence < 2r + ß.  相似文献   

3.
Remarks on Maximal Operators Over Arbitrary Sets of Directions   总被引:1,自引:0,他引:1  
Throughout this paper, we shall let be a subset of [0, 1] havingcardinality N. We shall consider to be a set of slopes, andfor any s , we shall let es be the unit vector of slope s inR2. Then, following [7], we define the maximal operator on R2associated with the set by The history of the bounds obtained on is quite curious. The earliest study of relatedoperators was carried out by Cordoba [2]. He obtained a boundof C(1 + log N) on the L2 operator norm of the Kakeya maximaloperator over rectangles of length 1 and eccentricity N. Thisoperator is analogous to with However, for arbitrary sets, the best known result seems to be C(1 + log N). This followsfrom Lemma 5.1 in [1], but a point of view which produces aproof appears already in [8]. However, in this paper, we provethe following.  相似文献   

4.
Packing, Tiling, Orthogonality and Completeness   总被引:3,自引:0,他引:3  
Let Rd be an open set of measure 1. An open set DRd is calleda ‘tight orthogonal packing region’ for if DDdoes not intersect the zeros of the Fourier transform of theindicator function of , and D has measure 1. Suppose that isa discrete subset of Rd. The main contribution of this paperis a new way of proving the following result: D tiles Rd whentranslated at the locations if and only if the set of exponentialsE = {exp 2i, x: } is an orthonormal basis for L2(). (This resulthas been proved by different methods by Lagarias, Reeds andWang [9] and, in the case of being the cube, by Iosevich andPedersen [3]. When is the unit cube in Rd, it is a tight orthogonalpacking region of itself.) In our approach, orthogonality ofE is viewed as a statement about ‘packing’ Rd withtranslates of a certain non-negative function and, additionally,we have completeness of E in L2() if and only if the above-mentionedpacking is in fact a tiling. We then formulate the tiling conditionin Fourier analytic language, and use this to prove our result.2000 Mathematics Subject Classification 52C22, 42B99, 11K70.  相似文献   

5.
In [1], Beardon introduced the Apollonian metric defined forany domain D in Rn by This metric is Möbius invariant, and for simply connectedplane domains it satisfies the inequality D2D, where D denotesthe hyperbolic distance in D, and so gives a lower bound onthe hyperbolic distance. Furthermore, it is shown in [1, Theorem6.1] that for convex plane domains, the Apollonian metric satisfies, and, by considering the example of the infinite strip {x + iy:|y|<1}, that the best possibleconstant in this inequality is at least . In this paper we makethe following improvements.  相似文献   

6.
Let be a pseudoconvex domain in C2 with smooth boundary, andlet be a smooth embedded analytic disc intersecting transversally along the curve A. Then A isknotted in . 2000 Mathematics Subject Classification 32U99.  相似文献   

7.
Using the BMO-H1 duality (among other things), D. R. Adams provedin [1] the strong type inequality whereC is some positive constant independent of f. Here M is theHardy–Littlewood maximal operator in Rn, H is the -dimensionalHausdorff content, and the integrals are taken in the Choquetsense. The Choquet integral of 0 with respect to a set functionC is defined by Precise definitionsof M and H will be given below. For an application of (1) tothe Sobolev space W1, 1 (Rn), see [1, p. 114]. The purpose of this note is to provide a self-contained, directproof of a result more general than (1). 1991 Mathematics SubjectClassification 28A12, 28A25, 42B25.  相似文献   

8.
A Banach algebra a is AMNM if whenever a linear functional on a and a positive number satisfy |(ab)–(a)(b)|||a||·||b||for all a, b a, there is a multiplicative linear functional on a such that ||–||=o(1) as 0. K. Jarosz [1] asked whetherevery Banach algebra, or every uniform algebra, is AMNM. B.E. Johnson [3] studied the AMNM property and constructed a commutativesemisimple Banach algebra that is not AMNM. In this note weconstruct uniform algebras that are not AMNM. 1991 MathematicsSubject Classification 46J10.  相似文献   

9.
Let f be a 1-periodic C1-function whose Fourier coefficientssatisfy the condition n|n|3|f(n|2 < . For every R\Q andm Z\{0}, we consider the Anzai skew product T(x, y) = (x +, y + mx + f(x)) acting on the 2-torus. It is shown that T hasinfinite Lebesgue spectrum on the orthocomplement L2(dx) ofthe space of functions depending only on the first variable.This extends some earlier results of Kushnirenko, Choe, Lemaczyk,Rudolph, and the author. 1991 Mathematics Subject Classification28D05.  相似文献   

10.
Let T be the Volterra operator on L2[0, 1] where f L2[0, 1], 0 x 1. It is well known that||n!Tn|| = O(1/n!). In a recent paper [1], D. Kershaw has provedthat a result which wasfirst conjectured by Lao and Whitley in [2]. It is easy to provethat For completeness, wegive the proof using the familiar Schmidt norm estimate forthe norm of an integral operator (see Section 2 below). Kershawproves that by analysingthe special positivity preserving properties of T*T. He usesone of the many abstract theorems on eigenvalues and eigenfunctionsof compact operators which preserve a cone. In this paper weshall reprove (1), giving a short and direct proof of (2). 1991Mathematics Subject Classification 47G10, 45-04.  相似文献   

11.
The norm of a group G is the subgroup of elements of G whichnormalise every subgroup of G. We shall denote it (G). An ascendingseries of subgroups i(G) in G may be defined recursively by:0(G) = 1 and, for i 0, i+1(G)/i(G) = (G/i(G)). For each i,the section i+1(G)/i(G) clearly contains the centre of the groupG/i(G). A result of Schenkman [8] gives a very close connectionbetween this norm series and the upper central series: i(G) i(G) 2i(G). 1991 Mathematics Subject Classification 20E15.  相似文献   

12.
Bull London Math. Soc, 4 (1972), 370–372. The proof of the theorem contains an error. Before giving acorrect proof, we state two lemmas. LEMMA 1. Let K/k be a cyclic Galois extension of degree m, let generate Gal (K/k), and let (A, I, ) be defined over K. Supposethat there exists an isomorphism :(A,I,) (A, I, ) over K suchthat vm–1 ... = 1, where v is the canonical isomorphism(Am, Im, m) (A, I, ). Then (A, I, ) has a model over k, whichbecomes isomorphic to (A, I, ) over K. Proof. This follows easily from [7], as is essentially explainedon p. 371. LEMMA 2. Let G be an abelian pro-finite group and let : G Q/Z be a continuous character of G whose image has order p.Then either: (a) there exist subgroups G' and H of G such that H is cyclicof order pm for some m, (G') = 0, and G = G' x H, or (b) for any m > 0 there exists a continuous character m ofG such that pm m = . Proof. If (b) is false for a given m, then there exists an element G, of order pr for some r m, such that () ¦ 0. (Considerthe sequence dual to 0 Ker (pm) G pm G). There exists an opensubgroup Go of G such that (G0) = 0 and has order pr in G/G0.Choose H to be the subgroup of G generated by , and then aneasy application to G/G0 of the theory of finite abelian groupsshows the existence of G' (note that () ¦ 0 implies that is not a p-th. power in G). We now prove the theorem. The proof is correct up to the statement(iv) (except that (i) should read: F' k1 F'ab). To removea minor ambiguity in the proof of (iv), choose to be an elementof Gal (F'ab/k2) whose image $$\stackrel{\&macr;}{\sigma}$$ in Gal (k1/k2) generates this last group. The error occursin the statement that the canonical map v : AP A acts on pointsby sending ap a; it, of course, sends a a. The proof is correct, however, in the case that it is possibleto choose so that p = 1 (in Gal (F'/k2)). By applying Lemma 2 to G = Gal (F'ab/k2) and the map G Gal(k1/k2) one sees that only the following two cases have to beconsidered. (a) It is possible to choose so that pm = 1, for some m, andG = G' x H where G' acts trivially on k1 and H is generatedby . (b) For any m > 0 there exists a field K, F'ab K k1 k2is a cyclic Galois extension of degree pm. In the first case, we let K F'ab be the fixed field of G'.Then (A, I, ), regarded as being defined over K, has a modelover k2. Indeed, if m = 1, then this was observed above, butwhen m > 1 the same argument applies. In the second case, let : (A, I, ) (A$$\stackrel{\&macr;}{\sigma}$$, I$$\stackrel{\&macr;}{\sigma }$$, $$\stackrel{\&macr;}{\sigma}$$) be an isomorphism defined over k1 and let v ... p–1 = µ(R). If is replaced by for some Autk1((A, I, )) then is replacedby P. Thus, as µ(R) is finite, we may assume that pm–1= 1 for some m. Choose K, as in (b), to be of degree pm overk2. Let m be a generator of Gal (K/k2) whose restriction tok1 is $$\stackrel{\&macr;}{\sigma }$$. Then : (A, I, ) (A$$\stackrel{\&macr;}{\sigma }$$, I$$\stackrel{\&macr;}{\sigma}$$, $$\stackrel{\&macr;}{\sigma }$$ = (A$$\stackrel{\&macr;}{\sigma}$$m, I$$\stackrel{\&macr;}{\sigma }$$m, $$\stackrel{\&macr;}{\sigma}$$m is an isomorphism defined over K and v mpm–1, ... m =pm–1 = 1, and so, by) Lemma 1, (A, I, ) has a model overk2 which becomes isomorphic to (A, I, over K. The proof may now be completed as before. Addendum: Professor Shimura has pointed out to me that the claimon lines 25 and 26 of p. 371, viz that µ(R) is a puresubgroup of R*t, does not hold for all rings R. Thus this condition,which appears to be essential for the validity of the theorem,should be included in the hypotheses. It holds, for example,if µ(R) is a direct summand of µ(F).  相似文献   

13.
For each d2 we construct a connected open set Rd such that = int (clos()), and for each k 1 and each p [1, ), the subsetWk, () fails to be dense in the Sobolev space Wk, p(), in thenorm of Wk, p(). 1991 Mathematics Subject Classification 46E35,46F05.  相似文献   

14.
On the ideals and singularities of secant varieties of Segre varieties   总被引:1,自引:0,他引:1  
We find minimal generators for the ideals of secant varietiesof Segre varieties in the cases of k(1 x n x m) for all k, n,m, 2(n x m x p x r) for all n, m, p, r (GSS conjecture for fourfactors), and 3(n x m x p) for all n, m, p and prove they arenormal with rational singularities in the first case and arithmeticallyCohen–Macaulay in the second two cases.  相似文献   

15.
The purpose of this paper is to answer some questions posedby Doob [2] in 1965 concerning the boundary cluster sets ofharmonic and superharmonic functions on the half-space D givenby D = Rn–1 x (0, + ), where n 2. Let f: D [–,+] and let Z D. Following Doob, we write BZ (respectively CZ)for the non-tangential (respectively minimal fine) cluster setof f at Z. Thus l BZ if and only if there is a sequence (Xm)of points in D which approaches Z non-tangentially and satisfiesf(Xm) l. Also, l CZ if and only if there is a subset E ofD which is not minimally thin at Z with respect to D, and whichsatisfies f(X) l as X Z along E. (We refer to the book byDoob [3, 1.XII] for an account of the minimal fine topology.In particular, the latter equivalence may be found in [3, 1.XII.16].)If f is superharmonic on D, then (see [2, 6]) both sets BZ andCZ are subintervals of [–, +]. Let denote (n –1)-dimensional measure on D. The following results are due toDoob [2, Theorem 6.1 and p. 123]. 1991 Mathematics Subject Classification31B25.  相似文献   

16.
1. Definition of the A-polynomial The A-polynomial was introduced in [3] (see also [5]), and wepresent an alternative definition here. Let M be a compact 3-manifoldwith boundary a torus T. Pick a basis , µ of 1T, whichwe shall refer to as the longitude and meridian. Consider thesubset RU of the affine algebraic variety R = Hom (1M, SL2C)having the property that () and (µ) are upper triangular.This is an algebraic subset of R, since one just adds equationsstating that the bottom-left entries in certain matrices arezero. There is a well-defined eigenvalue map given by taking the top-left entries of () and (µ).1991 Mathematics Subject Classification 57M25, 57M50.  相似文献   

17.
Exceptional Functions and Normality   总被引:1,自引:0,他引:1  
Yang proved in [10] that if f and f(k) have no fix-points forevery fF, where F is a family of meromorphic functions in adomain G and k a fixed integer, then F is normal in G. In thispaper we prove normality for families F for which every fF omits1 and f(k) omits 2, where 1 and 2 are analytic functions with. 1991 Mathematics SubjectClassification 30D35, 30D45.  相似文献   

18.
Let N be a bounded open set and C( ). Assume that has an extensionC() such that H–1().Then by the Riesz representation theorem there exists a unique

We show that u+ coincides with the Perron solutionof the Dirichlet problem

This extends recent results by Hildebrandt [Math. Nachr. 278(2005), 141–144] and Simader [Math. Nachr. 279 (2006),415–430], and also gives a possible answer to Hadamard'sobjection against Dirichlet's principle.  相似文献   

19.
In [8, 6] it was shown that for each k and n such that 2k >n, there exists a contractible k-dimensional complex Y and acontinuous map : Sn Y without the antipodal coincidence property,that is, (x)(–x) for all x Sn. In this paper it is shownthat for each k and n such that 2k > n, and for each fixed-pointfree homeomorphism f of an n-dimensional paracompact Hausdorffspace X onto itself, there is a contractible k-dimensional complexY and a continuous map :X Y such that (x)(f(x)) for all xX.Various results along these lines are obtained. 1991 MathematicsSubject Classication 55M10, 54C05.  相似文献   

20.
In this paper we study several kinds of maximal almost disjointfamilies. In the main result of this paper we show that forsuccessor cardinals , there is an unexpected connection betweeninvariants ae(), b() and a certain cardinal invariant md(+)on +. As a corollary we get for example the following result.For a successor cardinal , even assuming that < = and 2= +, the following is not provable in Zermelo–Fraenkelset theory. There is a +-cc poset which does not collapse andwhich forces a() = + < ae() = ++ = 2. We also apply the ideasfrom the proofs of these results to study a = a() and non(M).2000 Mathematics Subject Classification 03E17 (primary), 03E05(secondary).  相似文献   

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