上期课外练习参考解答

1.令cosx=t,t∈[-1,1],则f(t)=t+3+1/(t+3)在[-1,1]内的值域为:f(-1)≤f(e)≤f(1),即5/2≤y≤17/4.2.把已知方程化为x2-4x+4=0(x>1),即x=2.由题意得B/A=2,sinC/sinA=2,于是有B=2A,sinC=2sinA,而A+B+C=π,∴C=π-3A,∴sinC=sin3A=2sinA,即3sinA-4sin3A=2sinA.     

点到空间直线距离的一个公式

利用求条件极值的拉格朗日乘数法给出了空间中点P(x0,y0,z0)到直线A1x+B1y+C1z+D1=0A2x+B2y+C2z+D2=0距离的一个公式d=|(A1x0+B1y0+C1z0+D1)n2-(A2x0+B2y0+C2z0+D2)n1|/|n1×n2|,其中ni={Ai,Bi,Ci},(i=1,2)     

2007年普通高等学校招生全国统一考试 山东数学(理科)

一、选择题:本大题共12小题,共60分1.若z=cosθ isinθ(i为虚数单位),则使z2=-1的θ值可能是A.6πB.4πC.3πD.2π2.已知集合M={-1,1},N={x|21<2x 1<4,x∈Z},则M∩N=A.{-1,1}B.{-1}C.{0}D.{-1,0}3.下列几何体各自的三视图中,有且仅有两个A视.图①相②同的是B.①③C.①④D.②④4.设α∈-1,1,21,3,则使函数y=xα的定义域为R且为奇函数的所有α值为A.1,3B.-1,1C.-1,3D.-1,1,35.函数y=sin2x π6 cos2x 3π的最小正周期和最大值分别为A.π,1B.π,2C.2π,1D.2π,26.给出下列三个等式:f(xy)=f(x) f(y),f(x y)=f(x)f(y),f(x y)=f(x) f(y)…     

一个数学问题的简便证明

《数学通报》2004年第12期刊登了李明老师对1525号数学问题“△ABC中,求证:sin(A-30°) sin(B-30°) sin(C-30°)≤23.”的证明,但证明方法技巧性较高,其实该题有较便的证法.记录如下:证因为sin(A-30°) sin(B-30°) sin(C-30°)=2sinA B2-60°·cosA2-B sin(A B 30°)=2sinA B2-60°·cosA2-B sin(A B-60°)=-2sin2A B2-60° 2cosA2-B·sinA B2-60° 1=-2sinA B2-60°-cosA2-2B2 cos2A2-B2 1≤32(1)当且仅当cos2A-2B=1cosA-2B=2sinA B2-60°时“=”号成立.因为-90°相似文献   

2006年高考数学安徽卷

一、选择题:共12小题,每小题5分,共60分.1.复数1+3i3-i等于A.i B.-i C.3+i D.3-i2.设集合A={x||x-2|≤2,x∈R},B={y|y=-x2,-1≤x≤2},则R(A∩B)等于A.RB.{x|x∈R,x≠0}C.{0}D.3.若抛物线y2=2px的焦点与椭圆x62+y22=1的右焦点重合,则p的值为A.-2B.2C.-4D.44.设a,b∈R,已知命题p∶a=b;命题q∶(a2+b)2≤a22+b2,则p是q成立的A.必要不充分条件B.充分不必要条件C.充分必要条件D.既不充分也不必要条件5.函数y=2x,x≥0,-x2,x<0的反函数是A.y=x2,x≥0-x,x<0B.2x,x≥0-x,x<0C.y=x2,x≥0--x,x<0D.2x,x≥0--x,x<0第(6)题图6.将函数y=sinωx(…     

直线与椭圆位置关系的一个性质定理及其应用

定理　若直线l:Ax +By +C =0 (A2 +B2 ≠ 0 )与椭圆C :(x -x0 ) 2a2 + ( y - y0 ) 2b2 =1有公共点 ,则有(Aa) 2 + (Bb) 2 ≥ (Ax0 +By0 +C) 2 .证　由(x -x0 ) 2a2 + ( y - y0 ) 2b2 =1 ,可令x =x0 +acosθ,y =y0 +bsinθ ,代入Ax +By +C =0 (A2 +B2 ≠ 0 ) ,得A(x0 +acosθ) +B( y0 +bsinθ) +C =0 .整理得Aacosθ +Bbsinθ =- (Ax0 +By0 +C) .即 (Aa) 2 + (Bb) 2 sin(θ + φ) =- (Ax0 +By0 +C) (其中 φ为辅助角 ) .又 |sin(θ+ φ) |≤ 1 ,∴| - (Ax0 +By0 +C) |(Aa) 2 + (Bb) 2 ≤ 1 .即 (Aa) 2 + (Bb) 2 ≥ (Ax0 +By0…     

关于一个双参数三元不等式的研究

文[1]给出如下结论:设x,yz∈R+,则x/2x+y+z+y/2y+x+z+z/2z+x+y≤3/4.文[2]将这一结论进行指数推广,得到 　　定理A 设x,y,z ∈R+,0相似文献   

考点21 简单的线性规划

1.(湖南卷,4)已知点P(x,y)在不等式组x-2≤0,y-1≤0,x+2y-2≥0表示的平面区域上运动,则z=x-y的取值范围是().(A)[-2,-1](B)[-2,1](C)[-1,2](D)[1,2]2.(浙江卷,7)设集合A={(x,y)x,y,1-x-y是三角形的三边长},则A所表示的平面区域(不含边界的阴影部分)是().第2题图3.(全国卷,10)在坐标平面上,不等式组y≥x-1,y≤-3x+1所表示的平面区域的面积为().(A)2(B)23(C)322(D)24.(江西卷,14)设实数x,y满足x-y-2≤0,x+2y-4≥0,2y-3≤0.则xy的最大值是.5.(福建卷,14)非负实数x,y满足2x+y-4≤0,x+y-3≤0,则x+3y的最大值为.6.(山东卷,15)设x,y满足约束条…     

三角代换在解题中的应用

三角代换是数学中的一种重要代换,下面就几个典型例题说一下三角代换在解题中的应用.一、利用三角代换求函数值域或最值例1求函数的y=x+1-x2的值域分析:此题首先观察到函数定义域[-1,1]与正弦函数值域一致,因此可考虑用三角代换.解:令x=sinθθ∈-2π,2π则y=sinθ+1-sin2θ=sinθ+cosθ=2sinθ+4π由-2π≤θ≤2π有-4π≤θ+4π≤34π所以-22≤sinθ+4π≤2函数值域:[-1,2]例2求函数y=1+2cos2x-1+2sin2x的最值分析:不难发现(1+2cos2x)2+(1+2sin2x)2=4因此可联想是否可用平方三角代换呢?解:由(1+2cos2x)2+(1+2sin2x)2=4可设1+2cos2x=2sinθ…     

三、反三角函数、三角方程

A组一.选择题(以下各题中,有且仅有一个选择支是正确的): 1.函数y=lg(arccosx)的定义域是( )。 (A)-1≤x≤1;(B)-1≤x≤1; (C)-1相似文献   

A REPRESENTATION FORMULA RELATED TO SCHR(O)DINGER OPERATORS

Schr(o)dinger operator is a central subject in the mathematical study of quantum mechanics.Consider the Schrodinger operator H = -△ V on R, where △ = d2/dx2 and the potential function V is real valued. In Fourier analysis, it is well-known that a square integrable function admits an expansion with exponentials as eigenfunctions of -△. A natural conjecture is that an L2 function admits a similar expansion in terms of "eigenfunctions" of H, a perturbation of the Laplacian (see [7], Ch. Ⅺ and the notes), under certain condition on V.     

On a class of self-similar processes with stationary increments in higher order Wiener chaoses

We study a class of self-similar processes with stationary increments belonging to higher order Wiener chaoses which are similar to Hermite processes. We obtain an almost sure wavelet-like expansion of these processes. This allows us to compute the pointwise and local Hölder regularity of sample paths and to analyse their behaviour at infinity. We also provide some results on the Hausdorff dimension of the range and graphs of multidimensional anisotropic self-similar processes with stationary increments defined by multiple Wiener–Itô integrals.     

On a class of Riemann surfaces

It is considered the class of Riemann surfaces with dimT1 = 0, where T1 is a subclass of exact harmonic forms which is one of the factors in the orthogonal decomposition of the spaceΩH of harmonic forms of the surface, namely The surfaces in the class OHD and the class of planar surfaces satisfy dimT1 = 0. A.Pfluger posed the question whether there might exist other surfaces outside those two classes. Here it is shown that in the case of finite genus g, we should look for a surface S with dimT1 = 0 among the surfaces of the form Sg\K , where Sg is a closed surface of genus g and K a compact set of positive harmonic measure with perfect components and very irregular boundary.     

CONTENTS OF VOLUME 30

正~~     

Instructions for contributions

正Applied Mathematics-A Journal of Chinese Universities,Series B(Appl.Math.J.Chinese Univ.,Ser.B)is a comprehensive applied mathematics journal jointly sponsored by Zhejiang University,China Society for Industrial and Applied Mathematics,and Springer-Verlag.It is a quarterly journal with     

Journal of Mathematical Research with Applications Guide for Authors

正Journal overview:Journal of Mathematical Research with Applications(JMRA),formerly Journal of Mathematical Research and Exposition(JMRE)created in 1981,one of the transactions of China Society for Industrial and Applied Mathematics,is a home for original research papers of the highest quality in all areas of mathematics with applications.The target audience comprises:pure and applied mathematicians,graduate students in broad fields of sciences and technology,scientists and engineers interested in mathematics.     

Staircase transportation problems with superadditive rewards and cumulative capacities

A cumulative-capacitated transportation problem is studied. The supply nodes and demand nodes are each chains. Shipments from a supply node to a demand node are possible only if the pair lies in a sublattice, or equivalently, in a staircase disjoint union of rectangles, of the product of the two chains. There are (lattice) superadditive upper bounds on the cumulative flows in all leading subrectangles of each rectangle. It is shown that there is a greatest cumulative flow formed by the natural generalization of the South-West Corner Rule that respects cumulative-flow capacities; it has maximum reward when the rewards are (lattice) superadditive; it is integer if the supplies, demands and capacities are integer; and it can be calculated myopically in linear time. The result is specialized to earlier work of Hoeffding (1940), Fréchet (1951), Lorentz (1953), Hoffman (1963) and Barnes and Hoffman (1985). Applications are given to extreme constrained bivariate distributions, optimal distribution with limited one-way product substitution and, generalizing results of Derman and Klein (1958), optimal sales with age-dependent rewards and capacities.To our friend, Philip Wolfe, with admiration and affection, on the occasion of his 65th birthday.Research was supported respectively by the IBM T.J. Watson and IBM Almaden Research Centers and is a minor revision of the IBM Research Report [6].