勿忘(0)~(1/2)=0

我们知道 0 =0 ,但在解题过程中 ,却常常忽视了 ,这反映了我们考虑问题的片面性 .例 1　当α、β取什么范围内的值时 ,式子sin2αcosβ有意义 ?错解　由 sin2 α≥ 0知　 sin2 αcosβ≥ 0等价于 cosβ≥ 0 .即β∈ [2 kπ - π2 ,2 kπ π2 ](k∈ Z) .分析　因为学生牢记“实数的平方为非负数”,即α∈ R时 ,sin2 α≥ 0 .所以由sin2 αcosβ≥ 0推导出 cosβ≥ 0 .事实上 ,这漏掉了另一种情况 :sinα =0 ,cosβ∈ R时原式也有意义 .即α =kπ,且β∈ R,k∈ Z.正解　原式有意义等价于 cosβ≥ 0或sinα =0 .解得β∈ [2 kπ - π2 ,2 k…     

From a (G, k, 1) to a (Ck ⊕ G, k, 1) Difference Family

Given a subgroup N of an additive group G, a (G,N,k,1) difference family (DF) is a set D of k-subsets of G such that (d – d | d, d D, d d, D D) = G – N. Generalizing a construction by Genma, Jimbo, and Mishima [4], we give a new condition for realizing a (Ck G, Ck × {0}, k, 1)-DF starting from a (G, {0}, k, 1)-DF. Among the consequences, new cyclic Steiner 2-designs are obtained.     

公式2(S_0)1/2=S1/2 (S′)1/2的推广与应用

在高一《立体几何》中 ,关于台体 (棱台、圆台 )的中截面有这样的一个性质 :2Ｓ0 =Ｓ Ｓ′(《立体几何》Ｐ64 例 2及Ｐ80 习题十第 1 1题 ) .换句话说 ,台体 (棱台、圆台 )的上底面面积Ｓ′、中截面面积Ｓ0 、下底面面积Ｓ的算术平方根Ｓ′、Ｓ0 、Ｓ组成了一个等差数列 ,公差ｄ =12 Ｓ -Ｓ′ .是不是只有中截面与上、下底面的面积具有这种性质 ?其它截面与上、下底面的面积是否具有类似的性质 ?我们不仿看一下 .设台体 (棱台、圆台 )的上、下底面面积分别是Ｓ′、Ｓ ,台体 (棱台、圆台 )的高为ｎｈ ,设Ｓ1 、Ｓ2 …Ｓｎ- 1 分别是过台体 (…     

公式2(S_0)~1/=(S_上)~1/2 (S_下)~1/2的思考

设棱台的两底面积分别为Ｓ上,Ｓ下,棱台中截面面积为Ｓ０,则有２Ｓ０＝Ｓ上＋Ｓ下．此公式的结构使我们易于联想到解析几何的中点坐标公式．下面以三棱台为例探索问题的一般形式．为方便起见,这里约定棱台上、下底面,平行于底面的截面面积分别用Ｓ上,Ｓ下,Ｓ表示．...     

关于(X⊕Y)1的凸性

本文给出k-严格凸、(局部)k一致圆定义的几个等价形式.利用等价形式,讨论了(X⊕Y)₁的k-严格凸及(局部)k一致圆性.     

A Paley–Wiener Type Theorem for Singular Measures on $$(-1/2, 1/2)$$ ( - 1 / 2 , 1 / 2 )

Journal of Fourier Analysis and Applications - For a fixed singular Borel probability measure $$\mu $$ on $$(-1/2, 1/2)$$ , we give several characterizations of when an entire function is the...     

О Тригонометрическом (0, 2)-Интерполировании

.      

用x~(1/2)±y~(1/2)=(x y±(2xy~(1/2)))~(1/2)解题

公式若注意其特点,巧解妙证一些题,真是别有情趣。例1 求函数f(x)=1-cos2x 1 cos2x~(1/2)的最小正周期。解由(＊)得解由a在二象限知sina>0, cosa<0 由(＊)得原式=2 2cosa~(1/2) 1-sina~(1/2)-1 sina~(1/2)     

关于(X⊕Y)_1的凸性

本文绘出ｋ－严格凸、（局部）ｋ一致圆定义的几个等价形式．利用等价形式,讨论了（Ｘ(Ｘ）１的ｋ－严格凸及（局部）ｋ一致圆性．     

Ramsey Number of K_(2,s 1) vs.K_(1,n)

It is shown that the Ramsey number r(K_(2,s 1),K_(1,n))(?)n sn~(1/2) (s 3)/2 o(1) for large n,and r(K_(2,s 1),K_(1,n))∈{((q-1)~2/s) 1,((q-1)~2/s) 2},where n=((q-1)~2/s)-q 2 and q is a prime power such that s|(q-1).     

On the reduction (mod 1) of completely monotone functions (0, ∞)

Summary The Euler-Maclaurin summation formula and its harmonic analysis (Poisson) are applied to the case of functions which are completely monotone on an open half-line. What thus results is a curious class of Fourier series, which can be determined explicitly and which represent completely monotone functions on the first half of the period. A by-product is the complete monotony (on the first half-period) of the Bernoulli functions, whether the index is integral or fractional.     

关于无理方程((a-x)~(1/2))+((x-b)~(1/2))=(a-b)~(1/2)

这是现行初中代数教材上的一道习题: 解关于x的方程 (a-x)~(1/2)(x-b)~(1/2)=(a-b)~(1/2)(A) 限制在条件a≥b,b≤x≤a下,将(A)两边平方,得 2(a-x)(x-b)~(1/2)=0。方程的两根是x=a或x=b。研究了(A)型方程的特点后来解这类无理方程是相当简捷的.现举数例如下。例1 解方程(100-x)~(1/2)+(x-64)~(1/2)=6。解:将原方程化为(A)型:     

(a~(1/2))~2和(a~2)~(1/2)告状记

(a~(1/2))~2和(a~2)~(1/2)兄妹俩,一来到花果山就受到众猴儿的青睐,争相和他俩交朋友,哪知有的小猴对他俩不礼貌,有时还受到了委屈,于是他俩就到猴王那里去告状,兄妹俩来到猴王面前,深深行了个鞠躬礼说:“报告猴王,小猴儿常把我俩张冠李戴,用我俩来解题时,     

Intriguing Sets of Points of Q(2n, 2) \Q +(2n ? 1, 2)

Intriguing sets of vertices have been studied for several classes of strongly regular graphs. In the present paper, we study intriguing sets for the graphs Γ _n , n ≥ 2, which are defined as follows. Suppose Q(2n, 2), n?≥ 2, is a nonsingular parabolic quadric of PG(2n, 2) and Q ⁺(2n ? 1, 2) is a nonsingular hyperbolic quadric obtained by intersecting Q(2n, 2) with a suitable nontangent hyperplane. Then the collinearity relation of Q(2n, 2) defines a strongly regular graph Γ _n on the set Q(2n, 2) \ Q ⁺(2n ? 1, 2). We describe some classes of intriguing sets of Γ _n and classify all intriguing sets of Γ₂ and Γ₃.     

(a~(1/2))~2与(a~2)~(1/2)的辨析

(a~(1/2))2与(a~2)~(1/2)在二次根式中扮演着十分重要的角色,由于这两个二次根式的外表较相似,有些同学在运算中往往对它们产生了混淆,发生这样或那样的错误．下面谈谈这两个概念的区别与联系．     

(a~(1/2))~2与(a~2)~(1/2)的异同

<正>学习二次根式时,经常要遇到与二次根式有关的两个重要式子:(a^(1/2))(1/2))²与(a2与(a²)2)^(1/2).这两个式子在形式上很相近,既有不同点又有相同点,因此一不小心就很容易把它们混淆了.一、不同点1.运算顺序不同(a(1/2).这两个式子在形式上很相近,既有不同点又有相同点,因此一不小心就很容易把它们混淆了.一、不同点1.运算顺序不同(a^(1/2))(1/2))²是对实数a先开方再平方,表示a的算术平方根的平方;(a2是对实数a先开方再平方,表示a的算术平方根的平方;(a²)2)^(1/2)是对实数a先平方再开方,表示a的平方的算术平方根.