共查询到18条相似文献,搜索用时 93 毫秒
1.
研究了n阶中立型方程(x(t)-cx(t-τ)^(n)+p(t)x(g(t))=0,t≥t0,n≥1(*)正解的存在性,在p(t)常号和变号的情况下,给出了(*)存在衰减正解的充分条件,特别,这偏离 文「2」,「4-6」和「8-12」的有关结果。 相似文献
2.
一阶变系数中立型方程正解的存在性和渐近性 总被引:2,自引:0,他引:2
一阶变系数中立型方程正解的存在性和渐近性李万同(甘肃张掖师专数学系张掖734000)权宏顺(兰州大学数学系兰州730000)关键词:中立型方程;正解存在性;渐近性AMS(1991)主题分类:34C10.考虑一阶变系数中立型时滞微分方程(x(t)一ex... 相似文献
3.
In this paper the sufficient conditions for the existence of positive solutions of the neutral difference equations with positive and negative coefficients are established. The results improve some known conclusions in the literature 相似文献
4.
5.
考虑l+1阶中立型差分方程在对f较弱的限制条件下,本文绘出了方程(*)当p≠-1时存在正解的充分条件以及当p=-1时存在有界正解的充分必要条件. 相似文献
6.
考虑一阶具有正负系数中立型微分方程[x(t) -c(t)x(t -γ) ]+ p(t)x(t-τ) -Q(t)x(t-δ) =0 ,t≥t0 ,( )其中c,p ,Q ∈C( (t0 ,∞ ) ,R+) ,R+=( 0 ,∞ ) ,γ>0 ,t >δ≥ 0。我们获得了方程 ( )正解存在的充分条件。作为结果的推论 ,去掉了ZHANGBing_gen文 [4](《应用数学学报》1 996年第 2期 )中必需条件 ∫∞c0 p(t)dt=∞ ,其中 p(t) =p(t) -Q(t -τ+δ) ≥ 0 ,从而改进了文 [4]中相应结论。 相似文献
7.
8.
高阶非线性中立型方程正解的渐近性及存在性 总被引:2,自引:0,他引:2
本文利用非线性分析中半序方法和增算子不动点定理,对高阶非线性中立型方程正解的渐近性进行了详细分类,并且给出了各种类型正解存在的充要条件和具体例子. 相似文献
9.
10.
获得了偶数阶中立型泛函微分方程[a(t)x(t)-b(t)x(t-r)](n) q(t)f(x(t-σ))=0 (t≥0)存在最终正解的充分条件. 相似文献
11.
Tadeusz Jankowski 《Nonlinear Analysis: Theory, Methods & Applications》2012,75(2):913-923
We use a fixed point theorem due to Avery and Peterson to establish the existence of at least three non-negative solutions of some nonlocal boundary value problems to third order differential equations with advanced arguments. An example is given to illustrate the main results. 相似文献
12.
Multiple symmetric positive solutions of a class of boundary value problems for higher order ordinary differential equations 总被引:3,自引:0,他引:3
John R. Graef Chuanxi Qian Bo Yang 《Proceedings of the American Mathematical Society》2003,131(2):577-585
In this paper, the authors consider the boundary value problem
and give sufficient conditions for the existence of any number of symmetric positive solutions of (E)-(B). The relationships between the results in this paper and some recent work by Henderson and Thompson (Proc. Amer. Math. Soc. 128 (2000), 2373-2379) are discussed.
and give sufficient conditions for the existence of any number of symmetric positive solutions of (E)-(B). The relationships between the results in this paper and some recent work by Henderson and Thompson (Proc. Amer. Math. Soc. 128 (2000), 2373-2379) are discussed.
13.
Using the fixed point method we prove an existence result for positive solutions of nonlinear second order ordinary differential equations. An application to semilinear Schrödinger equations in exterior domains is also presented. Mathematics Subject Classification (2000) 34C10 相似文献
14.
In this paper, we prove that every solution of the first order nonlinear neutral differential equation
15.
16.
运用Krasnosel’skii不动点理论研究了一类含参泛函微分方程半正问题正周期解的存在性.获得了当参数充分小时正周期解的存在性结果以及半正问题正周期解存在的充分条件.丰富了一阶泛函微分方程解的存在性理论. 相似文献
17.
Consider the forced higher-order nonlinear neutral functional differential equation
where n,m , 1 are integers, , i + = [0,), C,Q
i, g C([t
0,), ), fi C(, ), (i = 1, 2, ...;, m). Some sufficient conditions for the existence of a nonoscillatory solution of above equation are obtained for general Q
i(t) (i = 1, 2, ... ,m) and g(t) which means that we allow oscillatory Qi(t) (i = 1, 2, ... ,m) and g(t). Our results improve essentially some known results in the references.Project was supported by the Special Funds for Major State Basic Research Projects (G19990328) and Hunan Natural Science Foundation of P.R. China (10371103). 相似文献
18.
Faiz A. Al-Khayyal 《Mathematical Programming》1991,51(1-3):247-255
We simplify a result by Mangasarian on the existence of solutions to the linear complementarity problem. The simplified condition gives a new geometric interpretation of the result. When used to characterize the matrix classesQ andQ
0, our condition suggests a finitely checkable sufficient condition forP andP
0.This work was supported in part by the Office of Naval Research under Contract No. N00014-86-K-0173, and by general research development funds provided by the Georgia Institute of Technology. 相似文献