共查询到20条相似文献,搜索用时 15 毫秒
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题 1 设函数 y =f( x)的定义域为 R,且满足 f( a + x) =f ( b- x) ,求 y =f ( x)的图像的对称轴方程 .题 2 设函数 y =f ( x)的定义域为 R,求函数 y =f ( a + x)与 y =f ( b - x)的图像的对称轴方程 .解 1 令 a + x =t,则 x =t- a,从而b - x =b + a - t,∴ f ( t) =f( b + a - t) ,即 f ( x) =f( b + a - x) ,∴ y =f ( x)的图像是轴对称图形 ,且对称轴方程为 x =b + a2 .解 2 令 a + x =t,则 x =t- a,从而b - x =b + a - t,∴ 函数 y =f ( a+ x)与 y =f ( b- x)的图像的对称轴即为 y =f ( t)与 y =f ( b+a - t)的图像的对称轴 ,… 相似文献
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一.题目 (2007年高考数学全国卷Ⅱ压轴题)已知f(x)=x^3-x.(1)求曲线y=f(x)在点M(t,f(t))处的切线方程。(2)设a〉0,如果过(a,b)可作曲线y=f(x)的三条切线,证明:-a〈b〈f(a)。 相似文献
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讨论了方程 a2 x( t-τ) + a1x( t-τ) + a0 x( t-τ) + b2 x( t) + b1x( t) + b0 x( t) =δ的部分解 相似文献
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主要讨论一类泛函微分方程x(t)=a(t)g(x(t))+b(t)f(x1)(t≥0)解的渐近表现.建立非振动解和振动解趋于零的充分条件. 相似文献
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考虑非线性二阶中立型微分方程,[a(t)x(t)-∑ from i=1 to m (p_i(t)x(τi(t)))]″-∫from n=a to b (f(t,ξ,x[g(t,ξ)])dσ(ξ))=0,t≥t_0,和相应不等式[a(t)x(t)-∑ from i=1 to m (p_i(t)x(τi(t)))]″-∫from n=a to b (f(t,ξ,x[g(t,ξ)])dσ(ξ))≥0,t≥t_0.存在正解是相互等价的.其中a(t),pi(t)∈C([t0,∞),R+),a(t)>0,τi(t)∈C(R~+,R~+),τi(t)t,limt→∞τi(t)=∞(i=1,2,…,m).g(t,ξ)∈C([t_0,∞)×[a,b],R+).g(t,ξ)是分别关于t和ξ的增函数.g(t,ξ)t,ξ∈[a,b],limt→∞,ξ∈[a,b]g(t,ξ)=∞.f(t,ξ,x)∈C([t_0,∞)×[a,b]×R,R+).当x>0时,xf(t,ξ,x)>0.σ(ξ)∈C([a,b],R),且σ(ξ)非减. 相似文献
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由于椭圆与双曲线具有统一的定义,所以二者具有很多统一的性质,本文给出这两种曲线的两个统一性质.定理1已知椭圆x2a2 y2b2=1的左,右顶点分别为A1,A2,已知直线l:x=t(|t|≠a,t≠0),P为l上一动点(P不在椭圆上),直线PA1与椭圆交于另一点M,直线PA2与椭圆交于另一点N,则MN与x轴交于定点.证直线PA2,PA1的斜率分别为k1,k2.联立b2x2 a2y2-a2b2=0,y=k1(x-a),(b2 a2k12)x2-2a3k12x a4k12-a2b2=0.解得xN=a(a2k12-b2)a2k12 b2,yN=-2ab2k1a2k12 b2(1)联立b2x2 a2y2-a2b2=0,y=k2(x a),解得xM=-a(a2k22-b2)a2k22 b2,yM=2ab2k2a2k22 b2(2)直线MN的… 相似文献
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91. IntroductionIn 1935, LandauLifshitz[1] proposed the fOllowing coupled system of the nonlinear evo-lution equationZr = --a,t x (2 x (b f H)) a,E x (b f A), (1.1)- 8E7 x H = -- aE, (1.2)0t- 0H 0ZV x E = ---- -- pfZ0t p7' (1'3)v. A gv. 2 = 0, v. E = 0, (l.4)where a1, a2, a, g are constants, cr1 2 0, a 2 0, Z(x,t) = (Z1(x,t), Z2(x,t), Z3(x,t))denotes the microscopic magnetization field, H = (H1 (x, f), H2(x, t), H3(x, t)) the magneticfield, E(x, t) = (E1(x, t), E2(x, t), E3(… 相似文献
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文[1]提出并证明了下面一对姐妹不等式:若a,b,c是正数,且a b c=1,则有1b c-ac 1a-ba1 b-c≥763,①1b c ac1 a ba1 b c≥1613.②以上两式当且仅当a=b=c=31时取等号.但文[1]证明过程较繁杂,本文给出一种简单证法,并将结论进行一定推广.1一对不等式的简证先证上述不等式①.记x=b c,y=c a,z=a b,则有00,即f(t)为下凸函… 相似文献
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本考虑方程(x(t)-cx(t-2[(t 1)/2]))' p(t)x(t) r(t)x(t-2[(t 1)/2])) q(t)x(t2[(t 1)/2]=0(a)和方程(x(t)-cx(t-[t]))'=a(t)x(t) b(t)x(t-[t]) p(t)x([t 1])(b)解的振动性质,得到方程(a)和(b)的解为振动解的充分条件。 相似文献
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本文将利用变上限定积分构造辅助函数的方法,建立并证明一类新的积分不等式。定理1设f(x)在[a,b]上连续,在(a,b)内可导,f(a)=0,如果.那么如果广(x)>l,那么不等式(l)反向,且仅当人x)20,入。)一x-a或几。)一lr-a+b_I。_。、上三二时等号成立。2”“。、——~。证明对于任意给定的t6[a,b」,构造函数对t求导数得:F’(t)二由厂(t)>O,知f()单调递增,又f()一O,故f()>O,tC[a,hi又O</(t)<1,.”.G’(t)>O,G(t)单调递增。”.’G(a)一O.”.G(t)>O即产(t)一G(t)f… 相似文献
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In this paper, the authors aim at proving two existence results of fractional differential boundary value problems of the form(P_(a,b)){D~αu(x) + f(x, u(x)) = 0, x ∈(0, 1),u(0) = u(1) = 0, D~(α-3)u(0) = a, u(1) =-b,where 3 α≤ 4, Dαis the standard Riemann-Liouville fractional derivative and a, b are nonnegative constants. First the authors suppose that f(x, t) =-p(x)t~σ, with σ∈(-1, 1)and p being a nonnegative continuous function that may be singular at x = 0 or x = 1and satisfies some conditions related to the Karamata regular variation theory. Combining sharp estimates on some potential functions and the Sch¨auder fixed point theorem, the authors prove the existence of a unique positive continuous solution to problem(P_(0,0)).Global estimates on such a solution are also obtained. To state the second existence result, the authors assume that a, b are nonnegative constants such that a + b 0 and f(x, t) = tφ(x, t), with φ(x, t) being a nonnegative continuous function in(0, 1)×[0, ∞) that is required to satisfy some suitable integrability condition. Using estimates on the Green's function and a perturbation argument, the authors prove the existence and uniqueness of a positive continuous solution u to problem(P_(a,b)), which behaves like the unique solution of the homogeneous problem corresponding to(P_(a,b)). Some examples are given to illustrate the existence results. 相似文献
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In this note, a theorem and its three corollaries on solution of the first order ordinary differential equation are given. Theorem Suppose that b, F∈C,a∈C~1,b(y)≠0. If a(t) and b(t) satisfy the equality a′(t)b(t)=1, (1) then the first order differential equation y′=b(y)F(x,a(y)) (2) has a solution y=f(u) (3) where u=u(x) is a solution of the equatien 相似文献
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函数y=a1x2+b1x+c1/a2x2+b2x+c2值域的求法,很多资料上给出方法是判别式(即△)法,而一旦自变量的范围给以限定,当△法失效时,还有其他方法吗?一般资料上就避而不谈了.要全面系统解决函数y=a1x2+b1x+c1/a2x2+b2x+c2值域的问题,本文以为需解决以下三个事情:①判别式法的过程和依据,②自变量有限制时还能用判别式法吗?③自变量有范围限制,问题可以归结为三类常见函数:反比例函数;y=t+c/t(c>0);y=t+c/t(c<0)的值域求法. 相似文献
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本文指出文[1]中的一个失误,给出了一类半线性方程周期边值问题a(t)x″+b(t)x′+g(t,x)=e(t),x(0)-x(2π)=x′(0)-xv(2π)=0一个新的等价方程组,应用整体反函数定理得到文[1]的所有结论. 相似文献
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白占兵 《应用泛函分析学报》2000,2(3):193-197
考察如下边值问题正解的存在性x″(t) λa(t) f (x(t) ,y(t) ) =0y″(t) λb(t) g(x(t) ,y(t) ) =0x(0 ) =x(1 ) =y(0 ) =y(1 ) =0其中 f ,g:R × R R ;a,b:[0 ,1 ] R .所有的函数都被假定是连续的 ,此外 f ,g满足某些增长性条件 .本文得到了一些正解的存在性结果 . 相似文献
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In this article, the author studies the boundedness and convergence for the {(x) = a(y) - f(x),(y) = b(y)β(x) - g(x) e(t),where a(y), b(y), f(x),g(x),β(x) are real continuous functions in y ∈ R or x ∈ R,β(x) ≥ 0 for all x and e(t) is a real continuous function on R = {t: t ≥ 0} such that the equation has a unique solution for the initial value problem. The necessary and sufficient conditions are obtained and some of the results in the literatures are improved and extended. 相似文献
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We obtained the Cα continuity for weak solutions of a class of ultraparabolic equations with measurable coeffcients of the form
δt u = δx(a(x, y, t)δx u) + b0(x, y, t)δxu + b(x, y, t)δyu, which generalized our recent results on KFP equations. 相似文献
δt u = δx(a(x, y, t)δx u) + b0(x, y, t)δxu + b(x, y, t)δyu, which generalized our recent results on KFP equations. 相似文献