共查询到18条相似文献,搜索用时 343 毫秒
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设d,a,k,n是适合4k^2n+1=da^2,k〉1,n〉2,d无平方因子的正整数;又设C(K)和h(K)分别是实二次域K=Q(√d)的理想类群和类数。本文证明了:当a〈0.5k^0.56n时,则h(K)≡0(mod n)和C(K)必有n阶循环子群。 相似文献
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设d无平方因子,h(d)是二次域Q(d)的类数,本文证明了:若1+4k2n=da2,a,k>1,n>2为正整数,且a<0.9k35n或n的奇素因子p和k的素因子q均适合(p,q-1)=1,则除(a,d,k,n)=(5,41,2,4)以外,h(d)≡0(modn).同时,我们猜测:上述结果中的条件(p,q-1)=1是不必要的. 相似文献
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丢番图方程与实二次域类数的可除性 总被引:3,自引:3,他引:0
设d无平方因子,h(d)是二次域的类数。本文证明了:在方程U ̄2-dV ̄2=4,(U,V)=1有整数解时,丢番图方程4x ̄(2n)-dy ̄2=-1,n>2无|y|>1的整数解;如果正整数a,k,n满足,k>1,n>2且而是Pell方程x ̄2-dy ̄2=-1的基本解,则h(d)≡0(modn)。 相似文献
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椭圆一个定理的又一初等证明 总被引:1,自引:0,他引:1
定理 椭圆C:x2a2+y2b2=1(a>b>0)有且仅有两条对称轴:直线x=0和y=0.文[1]指出,这个定理的证明一般要用到仿射几何知识,同时文[1]给出了一个初等证明.笔者再给出这个定理的又一种初等证明如下.定理的证明 易验证直线x=0和y=0均是椭圆C的对称轴.因点B(0,b)关于直线x=k(k≠0)的对称点B′(2k,b)不在椭圆C图1上,故直线x=k(k≠0)不是椭圆C的对称轴.设F1,F2是椭圆C的两个焦点,椭圆C的长轴A1A2关于直线l:y=kx+n(k,n至少有一个不等于零)的… 相似文献
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等差数列前n 1项同次幂和的递归关系 总被引:1,自引:0,他引:1
等差数列前n+1项同次幂和的递归关系李朝星(湖北师范学院435002)设a,d是任意实数但d≠0,k为非负整数.用Sk(n;a,d)表示等差数列a,a+d,a+2d,…,a+nd,…的前n+1项k次幂的和,即Sk(n;a,d)=ak+(a+d)k+(... 相似文献
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设f(z)=z+Σanz^n为单位园|z|<1内解析且平均单叶,记其族为M又设{f(z)/z}^λ=1+Σ^∞n=1Dn(λ),λ>0,本文说明了:定理一 若f∈M,λ>0,则:Σ^∞k=1{||Dk(λ)|-|Dk-1(λ)||/dk(λ)}^2≤An,n=2,3,…其中A为绝对常数。dk(h)=h(h+1)…(h+k-1)/k!当λ=1/2,f∈s时为I.V.Milm所证明。定理二 若f∈M并 相似文献
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祁永成 《数学年刊A辑(中文版)》1994,(3)
投{Xn,n≥1}i.i.d.,Xn,1≤Xn,2≤…≤Xn,n是X1,X2,…,Xn的次序统计量.对非负整数k,r,k+r≤n,令.本文研究当k=kn,r=rn满足min(k,r)→∞,max(k,r)→0时截断和Sn(k,r)的弱大数律.设βn>0,Cn∈R,文中给出了依概率收敛的充要条件. 相似文献
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两个不等式的简捷证法 总被引:1,自引:0,他引:1
下面给出的两类不等式问题,一般是通过代换的方法证明.本文给出直接简捷的证明.命题1 设xi∈R+(i=1,2,…,n)且x211+x21+x221+x22+…+x2n1+x2n=a(0<a<n),求证:x11+x2+x221+x22+…+x2n1+x2n≤a(n-a)①证 由题设易知:11+x21+11+x22+…+11+x2n=n-a.由于 11+x2k+n-aa·x2k1+x2k ≥211+x2k·n-aa·x2k1+k2k =2n-aa·xk1+x2k)(k=1,2,…,n),此n式相… 相似文献
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陈天平 《数学年刊A辑(中文版)》1994,(4)
设G(z)在|z|<ρ(ρ>1)中解析,且数据Re[G(ej2kπ/n)];k=0,1,…,n-1已给出,其中n=2ν+1,本文构造了一个ν次多项式Pν(z)满足插值条件Re[Pν(ej2kπ/n)]=Re[G(ej2kπ/n)],k=0,1,…,n-1.并估计了误差‖G(ejω)-Pν(ejω)‖.此外,还给出了一个Walsh类型的超收敛定理. 相似文献
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Litan Yan 《Stochastics An International Journal of Probability and Stochastic Processes》2013,85(1-2):47-56
Let X =( X t ) t S 0 be a continuous semimartingale given by d X t = f ( t ) w ( X t )d d M ¢ t + f ( t ) σ ( X t )d M t , X 0 =0, where M =( M t , F t ) t S 0 is a continuous local martingale starting at zero with quadratic variation d M ¢ and f ( t ) is a positive, bounded continuous function on [0, X ), and w , σ both are continuous on R and σ ( x )>0 if x p 0. Denote X 𝜏 * =sup 0 h t h 𝜏 | X t | and J t = Z 0 t f ( s ) } ( X s )d d M ¢ s ( t S 0) for a nonnegative continuous function } . If w ( x ) h 0 ( x S 0) and K 1 | x | n σ 2 ( x ) h | w ( x )| h K 2 | x | n σ 2 ( x ) ( x ] R , n >0) with two fixed constants K 2 S K 1 >0, then under suitable conditions for } we show that the maximal inequalities c p , n log 1 n +1 (1+ J 𝜏 ) p h Á X 𝜏 * Á p h C p , n log 1 n +1 (1+ J 𝜏 ) p (0< p < n +1) hold for all stopping times 𝜏 . 相似文献
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Marilyn Breen 《Journal of Geometry》1986,27(2):175-179
We will establish the following improved Krasnosel'skii theorems for the dimension of the kernel of a starshaped set: For each k and d, 0 k d, define f(d,k) = d+1 if k = 0 and f(d,k) = max{d+1,2d–2k+2} if 1 k d.Theorem 1. Let S be a compact, connected, locally starshaped set in Rd, S not convex. Then for a k with 0 k d, dim ker S k if and only if every f(d, k) lnc points of S are clearly visible from a common k-dimensional subset of S.Theorem 2. Let S be a nonempty compact set in Rd. Then for a k with 0 k d, dim ker S k if and only if every f (d, k) boundary points of S are clearly visible from a common k-dimensional subset of S. In each case, the number f(d, k) is best possible for every d and k. 相似文献
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关于虚二次域类数的可除性 总被引:2,自引:0,他引:2
设α>1,b>1,(α,b)=1,h(-αb)表虚二次域的类数。如果有正整数x,y,n,k满足(1)αx ̄2+by ̄2=4k ̄n,b且;或(2)αx ̄2+by ̄2=k ̄n,x|α,y|b且αb≡2(mod4),则本文证明了关于h(-αb)的可除性的两个定理(见定理1,2),其中符号x|α表示x的每一个素因子整除α。 相似文献
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<正> 設K與L為拓撲空間,又設f:K→L為連續映像.由f導出了準同模對應f~n:H~n(L,G)→H~n(K,G),n=1,2,…,其中H~n(L,G),H~n(K,G)表示上同調羣,而G表示係數環或域以γ_p~n(K)或者 相似文献
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A. L. Yampol'skii 《Journal of Mathematical Sciences》1994,72(4):3261-3266
Let Mn denote an n-dimensional Riemannian manifold. Its metric is called -strongly spherical if at every point Q Mn there exists a -dimensional subspace Q
TQMn such that the curvature operator of the metric of Mn satisfies R(X, Y) Z = k(< Y, Z > X < X, Z > Y), where k = const > 0, Y Q
, X, Z #x2208; TQMn. The number is called the index of sphericity and k the exponent of sphericity. The following theorems are proved in the paper.THEOREM 1. Let the Sasakian metric of T1Mn be -strongly spherical with exponent of sphericity k. The following assertions hold: a) = 1 if and only if M2 has constant Gaussian curvature K 1 and k = K2/4; b) = 3 if and only if M2 has constant curvature K = 1 and k = 1/4; c) = 0, otherwise.THEOREM 2. Let the Sasakian metric of T1Mn (n Mn) be -strongly spherical with exponent of sphericity k. If k > 1/3 and k 1, then = 0. Let us denote by (Mn, K) a space of constant curvatureK. THEOREM 3. Let the Sasakian metric of T1(Mn, K) (n 3) be -strongly spherical with exponent of sphericity k. The following assertions hold: a) = 1 if and only if K = 1/4; b) = 0, otherwise. In dimension n = 3 Theorem 2 is true for k {1/4, 1}.Translated from Ukrainskii Geometricheskii Sbornik, No. 35, pp. 150–159, 1992. 相似文献
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Anant P. Godbole Stavros G. Papastavridis Robert S. Weishaar 《Annals of the Institute of Statistical Mathematics》1997,49(1):141-153
Consider a sequence of n independent Bernoulli trials with the j-th trial having probability pj of success, 1 j n. Let M(n,K) and N(n, K) denote, respectively, the r-dimensional random variables (M(n, k1),..., M(n,kr) and (N(n,k1), ..., N(n, kr)), where K = (k1, k2, ..., kr) and M(n, s) [N(n, s)] represents the number of overlapping [non-overlapping] success runs of length s. We obtain exact formulae and recursions for the probability distributions of M(n, K) and N(n, K). The techniques of proof employed include the inclusion-exclusion principle and generating function methodology. Our results have potential applications to statistical tests for randomness. 相似文献