共查询到20条相似文献,搜索用时 15 毫秒
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一、设题:乘法达一千道,五数加法六十道,道道答数绝妙无比。
二、乘法教例:294×429=126,126
315×429=135,135
791×429=339,339
五图中有被乘数125个,乘数8个(见图右),共有乘法题一千道,道道答数都是ABE,ABC排列形式。 相似文献
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Assume that each completely irrational noncommutative torus is realized as an inductive limit of circle algebras, and that for a completely irrational noncommutative torus Aw of rank m there are a completely irrational noncommutative torus Aρ of rank m and a positive integer d such that tr(Aw)=1/d.tr(Aρ).It is proved that the set of all C^*-algebras of sections of locally trivial C^*-algebra bundles over S^2 with fibres Aω has a group sturcture,denoted by π1^s(Aut(Aω)),which is isomorphic to Zif Ed>1 and {0} if d>1.Let Bcd be a cd-homogeneous C^*-algebra over S^2×T^2 of which no non-trivial matrix algebra can be factored out.The spherical noncommutative torus Sρ^cd is defined by twisting C^*(T2×Z^m-2) in Bcd ×C^*(Z^m-3) by a totally skew multiplier ρ on T^2×Z^m-2。It is shown that Sρ^cd×Mρ∞ is isomorphic to C(S^2)×C^*(T^2×Z^m-2,ρ)× Mcd(C)×Mρ∞ if and only if the set of prime factors of cd is a subset of the set of prime factors of p. 相似文献
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Wu Shengjian 《数学年刊B辑(英文版)》1994,15(4):453-462
Suppose that f(z)is a meromorphic function of order λ(0<λ<+∞)and of lower order μ in the plane.Let ρ be a positive number such that μ≤ρ≤λ.(1)If f^(l)(z)(0≤l<+∞)has p(1≤p<+∞)finite nonzero deficient valnes αi(i=1,…,p)with deficiencies δ(αi,f^(l)),then f(z)has a (0,∞)accumulative line of order ≥ρin any angular domain whose vertex is at the origin and whose magnitude is larger than max(π/ρ,2π-4/ρ ∑i=1^p arcsin √δ(αi,f^(l))/2).(2)If f(z) has only p(0<p<+∞)(0,∞),accumulative lines of order≥ρ:arg z=θk(0≤θ1<θ2<…<θp<2π,θp+1=θ1+2π),then λ≤π/ω,where ω=min I≤k≤p(θk+1-θk),provided that f^(l)(z)(0≤l<+∞)has a finite nonzero deficient value. 相似文献
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20世纪下半叶,有三位大师艾萨克·阿西莫夫、卡尔·萨根和马丁·加德纳,他们在美国科普界叱咤风云数十年.时至今日,前面两位大师均已逝世,唯有加德纳先生依然健在并且老当益壮,在数学传播领域继续发挥着他无可替代的作用.人们赞誉他为“数学的传教士”和“数学游戏大王”,并且认为他在当代数学界“占有一个独一无二的位置”. 相似文献
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20 0 3年 1 2月号问题解答(解答由问题提供人给出 )1 466 设M =5 2 0 0 1 + 72 0 0 2 + 92 0 0 3+ 1 1 2 0 0 4 ,求证 :M能被 8整除 .证明 令An =5 2n- 1 ,Bn =72n,Cn =92n- 1 ,Dn =1 1 2n(n∈Z+)( 1 )当n=1时 ,有A1 =5 ,B1 =49,C1 =9,D1 =1 2 1 ,所以A1 除以 8余 5 ;B1 除以 8余 1 ;C1 除以 8余 1 ;D1 除以 8余 1 .( 2 )假定n=k(k∈Z+)时 ,有Ak 除以 8余 5 ,即Ak =5 2k- 1 =8S1 + 5 (S1 ∈Z+) ;Bk=72k除以 8余 1 ,即Bk=72k=8S2 + 1 (S2∈Z+) ;Ck =92k- 1 除以 8余 1 ,即Ck =92k- 1 =8S3+1 (S3∈Z+) ;Dk =1 1 2k 除以 8余 1 … 相似文献
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用矩阵的初等变换解矩阵方程Am×nXn×s=Bm×s 总被引:1,自引:1,他引:0
本文通过对一般的矩阵方程Am×nXn×s=Bm×s?B5木卣驛和B作初等行变换及初等列变换,给出了一般矩阵方程的求解方法。 相似文献
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《中学生数学》2003,(21)
高一年级1.( 1)易知△ABC为直角三角形 .由OC2 =OA×OB ,得 4×OB2 =42 ,∴ OB =2 , OA =8.过A( -8,0 ) ,B( 2 ,0 )的抛物线解析式设为 :y =a(x +8) (x -2 ) .将C( 0 ,4)代入得 a =-14 .∴ y =-14 (x +8) (x -2 ) .( 2 )易求得D( -3 ,2 54) ,S△ADC=12 [2 54-48× ( 8-2 ) ]× 8=13 .2 . -3 016x2 -2 ( 5 -k)x +16>0 Δ1 =( 5 +k) 2 -14 2 <0Δ2 =( 5 -k) 2 -162 <0 -19相似文献
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二、3乘(一)本个数位乘数0246813579本个数0628439517(二)进数位乘数0123456789本个数0000111222(三)位积位积=本个+后进(允许够10数)合成位积的训练最好先用一笔清,然后再用脑算盘清理。有够10进位用“左手”。够10进位多数是后数有3与6的地方。例13×37,269........||||||||||虚半替半||||||||||}}够4进1够7进23×37269=0117073进03本个9,7进2,为17本个12本个6,6进1,为76本个8,9进2,为09本个7脑算盘清理为111,807。例23×68,194脑算盘清理为204,582。例33×94,762例43×29,507三、4乘(一)本个数位乘数0246813579本个… 相似文献
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我们记Tk为Galois环GR(2^k,m)到Z2^k的迹映射,ξ是GR(2^k,m)中的本原元,ξ2^m-1=1,ιk,m={0,1,ξ,…,ξ2^m-2},来讨论一类Z2^k-线性码{Tk(a0x 2^k-2a1x^3 2^k-1,a2x^5) b|a0∈GR(2^k,m),a1∈ιk,m 2ιk,m,a2∈ιk,m,b∈Z2^k}x∈ιk的广义Gray映射下的象所构成的二元码,这类二元码也具有很好的参数性质,优于一些已知的二元码,例如广义的Kerdock码或广义的Delsarte-Goethals码。 相似文献
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HuoZhaohui GuoBoling 《偏微分方程(英文版)》2004,17(2):137-151
The well-posedness of the Cauchy problem for the system{iδtu+δx^2u=uv+|u|^2u,t,x∈IR,δtv+δxHδxv=δx|u|^2,u(0,x)=u0(x),v(0,x)=v0(x),is considered. It is proved that there exists a unique local solution (u(x,t), v(x,t))∈C([0,T);H^s)×C([0,T);Hs^-1/2) for any initial data (u0,v0)∈H^s(IR)×H^s-1/2(IR)(s≥1/4) and the solution depends continuously on the initial data. 相似文献
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在Qp空间上建立了Jackson型不等式,即对任意f(z)=∑j=0 ^∞ αjz^j∈Qp,0≤p〈∞,α〉1及k-1∈N,有
||f(z)-Г(k)/Г(k+α)∑ j=0 ^k-1Г(k-j+α)/Г(k-j)αjz^j||Qp≤C(α)ω(1/k,f,Qp),其中ω(1/k,f,Qp)为Qp空间中的连续模,C(α)是仅与参数α有关的正常数. 相似文献
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设K为四次循环数域,k为其二次子域,记h(L)为域L的理想类数。本文得到h-=h(K)/h(k)的十个同余公式。特别若,素数p=r2+s2,s为偶数,则当p≡1(8)时,C1h-≡B(p-1)/4B3(p-1)/4(mod ρ),Bn是Bernoulli数;当ρ≡5(8)时,C2h-≡E(ρ-5)/8E(3ρ-7)/8(mod ρ),En是Euler数。若实则。若3在K=Q(√θ)分歧,则C4h-≡h(K*)/h(k)(mod 3),K*=Q(√3θ).Ci均为明显给出常数.此外还得到h-可能因子的一些关系。这些结果相当于系统地把Ankeny-Arun-Chowla,Kiselev,Carlitz,陆洪文等从1948到1983年关于二次域的许多结果推广到四次循环域上去。 相似文献
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LU Guangshi 《数学年刊B辑(英文版)》2005,26(2):291-304
It is proved that each sufficiently large integer N=5(mod24) can be written as N=p1^2+p2^2+p3^2+p4^2+p5^2 with|pj=√N/5|±、≤U=N^1/2-1/35+e,where pj ae primes.This result,which is obtained by an iterative method and a hybrid estimate for Dirichlet polynomial, improves the previous results in this direction. 相似文献
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ShiPeihu 《偏微分方程(英文版)》2004,17(4):369-383
In this paper we deal with the self-similar singular solution of the p-Laplacian evolution equation ut = div(|△↓u|^p-2△↓u) -|△↓|^q for p > 2 and q > 1 in R^n× (0, ∞). We prove that when p > q + n/(n + 1) there exist self-similar singular solutions, while p≤q+n/(n+1) there is no any self-similar singular solution. In case of existence, the self-similar singular solutions are the self-similar very singular solutions,which have compact support. Moreover, the interface relation is obtained. 相似文献