修正冒泡排序网络的边偶泛圈性

对于一个二部图G,如果在G中存在任意长为偶数l(4≤l≤|V(G)|)的圈,则称这个二部图G是偶泛圈的:如果对G中任意一边e,在G中存在任意长为偶数l(4≤l≤|V(G)|)且包含e的圈,则称这个二部图G是边偶泛圈的.修正冒泡排序网络是互连网络中的一个重要的Cayley图模型.在此,证明了对任意的自然数n,当n≥3时,修正冒泡排序网络Y_n是偶泛圈的,同时也是边偶泛圈的.     

Hamilton非二部图的弱泛圈性

图G称为弱泛圈图是指G包含了每个长为t(g(V)≤l≤c(G))的圈,其中g(G),c(v)分别是G的围长与周长.1997年Brandt提出以下猜想:边数大于[n2/4]-n 5的n阶非二部图为弱泛圈图.1999年Bollobas和Thomason证明了边数不小于[n2/4]-n 59的n阶非二部图为弱泛圈图.作者证明了如下结论:设G是n阶Hamilton非二部图,若G的边数不小于[n2/4]-n 12,则G为弱泛圈图.     

Hamiltonian[k,k+1]-因子

本文考虑n/2-临界图中Hamiltonian[k,k+1]-因子的存在性。Hamiltonian[k,k+1]-因子是指包含Hamiltonian圈的[k,k+1]-因子;给定阶数为n的简单图G,若δ(G)≥n/2而δ(G\e)相似文献   

关于完全3-部图K1,6,n的交叉数

早在上世纪五十年代,Zarankiewicz猜想完全2-部图Km,n(m≤n)的交叉数为[m/2][m-1/2][n/2][n-1/2](对任意实数x,[x]表示不超过x的最大整数)．目前这一猜想的正确只证明了当m≤6时成立．本文主要证明了若Zarankiewicz猜想对m=7成立,则完全3-部图K1,6,n的交叉数为9[n/2][n-1/2] 6[n/2]．     

完全3-部图K_(1，10，n)的交叉数

在上世纪五十年代初,Zarankiewicz猜想完全2-部图Km,m(m≤n)的交叉数为[m/2][m-1/2][n/2][n-1/2](对任意实数x,[x]表示不超过x的最大整数),目前只证明了当m ≤ 6时,Zarankiewicz猜想是正确的.假定Zarankiewicz猜想对m=11的情形成立,本文确定完全3-部图K1,10,n的交叉数.     

循环分布图最大边数猜想的一个反例

令f(n)为恰有n个顶点，任意两个循环长度都不相等的图的最多边数．1975年，Erdos提出确定f(n)的问题(见[1]P274，Problem11)．1986年．Y．Shi证明了对任意自然数．≥3，有f(n)≥n [(√8n-23 1／1)／2]，且当3≤n≤17时．等号成立．进而猜想：对于任何自然数n≥3，上述等式都成立．本文对该猜想给出一个反例。     

关于超立方体网络的(d,k)独立数

(d,k)独立数是分析互连网络性能的一个重要参数.对于任意给定的图G和正整数d和k,确定G的(d,k)独立数问题是一个NPC问题.因此,确定一些特殊图的(d,k)独立数显得很重要.本文确定了k维超立方体网络的(d,k)独立数等于2,如果d=k≥4或者d=k-1≥6 以及αd,k-t(Qk)=αd,k(Qk),其中0≤t≤k-2,1≤d≤k-t-1.     

折叠立方体网络的最小反馈点集

对简单图G=(V,E),顶点子集F V,如果由V\F导出的子图不含圈,则称F是G的反馈点集。点数最小的反馈点集称图的最小反馈点集,最小的点数称为反馈数。一个k维折叠立方体是由一个k维超立方体加上所有的互补边构成的图。本文证明了k维折叠立方体网络的反馈数f(k)=c.2k-1(k 2),其中c∈k-1     

故障超立方体中经过指定路的无故障圈

研究了在含有故障点和（或）故障边的n维超立方体Qn中经过给定路的无故障圈问题,得到以下结果：设Fv V（Qn）,Fe E（Qn）.若｜Fv｜＋｜Fe｜≤n-h且3≤h≤n,或｜Fv｜＋｜Fe｜≤n-3且h=2,则在Qn-Fv-Fe中,每一条长度等于h的路P都包含在每个偶长度从2h＋2到2^n-2｜Fv｜的圈中.并且若又有条件｜Fv｜＋｜Fe｜〈h-1时,则路P还包含在长度等于2h的无故障的圈中.     

广义超立方体网络中一类容错路由选择

证明了n-维广义超立方体网络Q(m1,m2,…,mn)中,任意两个节点x和y之间存在长度均不超过H(x,y)+2的m1+m2+…+mn-n条内点不交的路由,其中有H(x,y)条长度不超过H(x,y),此处H(x,y)表示x到y的汉明距离.并在此基础上讨论了广义超立方体网络的容错路由问题.证明了即使无效点很多,但只要存在某个(n-1)-维广义超子立方体中无效节点较少,则该n-维广义超立方体中的任意两个有效节点之间可以找到最优路由或接近最优路由的有效路由.     

图K_nH_((5n/2)-4)的升分解

Ａｌａｖｉ等人给出了图的升分解的概念并猜测任何一个有正数条边的图都可以升分解．Ｆａｕｄｒｅｅ等１９８７年证明了当完全图Ｋｎ的子图Ｈ至多有ｎ—１条边时，Ｋｎ－Ｈ可以升分解．马克杰等１９９７年证明了当Ｈ至多含有ｎ条边时，Ｋｎ－Ｈ可以升分解．作者１９９９年证明了当Ｈ的边数小于３ｎ／２时，Ｋｎ－Ｈ可以升分解．本文将证明当Ｈ的边数小于（５ｎ／２）－４时Ｋｎ－Ｈ有升分解．     

A note on the Three Color Problem on planar graphs without 4- and 5-cycles and without ext-triangular 7-cycles

Steinberg conjectured in 1976 that every planar graph with no cycles of length four or five is 3-colorable. This conjecture is disproved by constructing a planar graph with no cycles of length four or five but intersecting triangles. Jin et al. proved that plane graphs without 4- and 5-cycles and without ext-triangular 7-cycles are 3-colorable [SIAM J. Discrete Math. 31 (3) (2017) 1836–1847]. In this paper, we point out a mistake of their proof and give an improved proof.     

The number of vertices whose out-arcs are pancyclic in a 2-strong tournament

An arc going out from a vertex x in a digraph is called an out-arc of x. Yao et al. [Discrete Appl. Math. 99 (2000) 245-249] proved that every strong tournament contains a vertex x such that all out-arcs of x are pancyclic. Recently, Yeo [J. Graph Theory 50 (2005) 212-219] proved that each 3-strong tournament contains two such vertices. In this paper, we confirm that Yeo's result is also true for 2-strong tournaments. Our proof implies a polynomial algorithm to find two such vertices.     

Every tree contains a large induced subgraph with all degrees odd

Caro et al. [3] proved that every tree of order n contains an induced subgraph of order at least n/2 with all degrees odd, and conjectured a better bound. In this note we prove that every tree of order n contains an induced subgraph of order at least with all degrees odd; this bound is best possible for every value of n.     

Planar graphs without triangles adjacent to cycles of length from 4 to 7 are 3-colorable

It is known that planar graphs without cycles of length from 4 to 7 are 3-colorable (Borodin et al., 2005) [13] and that planar graphs in which no triangles have common edges with cycles of length from 4 to 9 are 3-colorable (Borodin et al., 2006) [11]. We give a common extension of these results by proving that every planar graph in which no triangles have common edges with k-cycles, where k∈{4,5,7} (or, which is equivalent, with cycles of length 3, 5 and 7), is 3-colorable.     

An optimal solution to a three echelon supply chain network with multi-product and multi-period

Recently, Kadadevaramath et al. (2012) [1] presented a mathematical model for optimizing a three echelon supply chain network. Their model is an integer linear programming (ILP) model. In order to solve it, they developed five algorithms; four of them are based on a particle swarm optimization (PSO) method and the other is a genetic algorithm (GA). In this paper, we develop a more general mathematical model that contains the model developed by Kadadevaramath et al. (2012) [1]. Furthermore, we show that all instances proved in Kadadevaramath et al. (2012) [1] can easily be solved optimally by any integer linear programming solver.     

VERTEX-FAULT-TOLERANT CYCLES EMBEDDING ON ENHANCED HYPERCUBE NETWORKS

In this paper, we study the enhanced hypercube, an attractive variant of the hypercube and obtained by adding some complementary edges from a hypercube, and focus on cycles embedding on the enhanced hypercube with faulty vertices. Let Fu be the set of faulty vertices in the n-dimensional enhanced hypercube Qn,k （n ≥ 3, 1 ≤ k 〈≤n - 1）. When IFvl = 2, we showed that Qn,k - Fv contains a fault-free cycle of every even length from 4 to 2n - 4 where n （n ≥ 3） and k have the same parity; and contains a fault-free cycle of every even length from 4 to 2n - 4, simultaneously, contains a cycle of every odd length from n-k ＋ 2 to 2^n-3 where n （≥ 3） and k have the different parity. Furthermore, when ｜Fv｜ = fv ≤ n - 2, we prove that there exists the longest fault-free cycle, which is of even length 2^n - 2fv whether n （n ≥ 3） and k have the same parity or not; and there exists the longest fault-free cycle, which is of odd length 2^n - 2fv ＋ 1 in Qn,k - Fv where n （≥ 3） and k have the different parity.     

平面图3色可染的一个充分条件

Steinberg猜想既没有4-圈又没有5-圈的平面图是3色可染的. Xu, Borodin等人各自独立地证明了既没有相邻三角形又没有5-和7-圈的平面图是3 色可染的. 作为这一结果的推论, 没有4-, 5-和7-圈的平面图是3色可染的. 本文证明一个比此推论更接近Steinberg猜想的结果, 设G是一个既没有4-圈又没有5-圈的平面图, 若对每一个k∈{3, 6, 7}, G都不含(k, 7)-弦, 则G是3色可染的, 这里的(k, 7)-弦是指长度为7+k-2的圈的一条弦, 它的两个端点将圈分成两条路, 一条路的长度为6, 另一条路的长度为k-1.     

Acyclic 5-choosability of planar graphs without 4-cycles

The conjecture on the acyclic 5-choosability of planar graphs (Borodin et al., 2002) as yet has been verified only for several restricted classes of graphs: those of girth at least 5 (Montassier, Ochem, and Raspaud, 2006), without 4- and 5-cycles or without 4- and 6-cycles (Montassier, Raspaud, and Wang, 2007), with neither 4-cycles nor chordal 6-cycles (Zhang and Xu, 2009), with neither 4- cycles nor two 3-cycles at distance less than 3 (Chen and Wang, 2008), and with neither 4-cycles nor intersecting 3-cycles (Chen and Raspaud, 2010). Wang and Chen (2009) proved that the planar graphs without 4-cycles are acyclically 6-choosable. We prove that a planar graph without 4-cycles is acyclically 5-choosable, which is a common strengthening of all above-mentioned results.