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1.
Let f, g: (Rn, 0) (Rp, 0) be two C map-germs. Then f and gare C0-equivalent if there exist homeomorphism-germs h and lof (Rn, 0) and (Rp, 0) respectively such that g = l f h–1.Let k be a positive integer. A germ f is k-C0-determined ifevery germ g with jk g(0) = jk f(0) is C0-equivalent to f. Moreover,we say that f is finitely topologically determined if f is k-C0-determinedfor some finite k. We prove a theorem giving a sufficient conditionfor a germ to be finitely topologically determined. We explainthis condition below. Let N and P be two C manifolds. Consider the jet bundle Jk(N,P) with fiber Jk(n, p). Let z in Jk(n, p) and let f be suchthat z = jkf(0). Define Whether (f) < k depends only on z, not on f. We can thereforedefine the set Let Wk(N, P) be the subbundle of Jk(N, P) with fiber Wk(n, p).Mather has constructed a finite Whitney (b)-regular stratificationSk(n, p) of Jk(n, p) – Wk(n, p) such that all strata aresemialgebraic and K-invariant, having the property that if Sk(N,P) denotes the corresponding stratification of Jk(N, P) –Wk(N, P) and f C(N, P) is a C map such that jkf is multitransverseto Sk(N, P), jkf(N) Wk(N, P) = and N is compact (or f is proper),then f is topologically stable. For a map-germ f: (Rn, 0) (Rp, 0), we define a certain ojasiewiczinequality. The inequality implies that there exists a representativef: U Rp such that jkf(U – 0) Wk (Rn, Rp = and suchthat jkf is multitransverse to Sk (Rn, Rp) at any finite setof points S U – 0. Moreover, the inequality controlsthe rate jkf becomes non-transverse as we approach 0. We showthat if f satisfies this inequality, then f is finitely topologicallydetermined. 1991 Mathematics Subject Classification: 58C27.  相似文献   

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Nash-Williams [6] formulated a condition that is necessary andsufficient for a countable family A=(Ai)iI of sets to have atransversal. In [7] he proved that his criterion applies alsowhen we allow the set I to be arbitrary and require only thatiJAi=Ø for any uncountable JI. In this paper, we formulateanother criterion of a similar nature, and prove that it isequivalent to the criterion of Nash-Williams for any familyu. We also present a self-contained proof that if iJAi=Øfor any uncountable JI, then our condition is necessary andsufficient for the family u to have a transversal.  相似文献   

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詹杨新 《大学数学》2011,27(2):62-67
在用广义Vandermonde行列式给出Hermite插值多项式的表达式的基础上,针对a<,i>=2(i=1,2,…,s)的情形给出向量值切触有理插值存在性问题有解的条件及表达式.  相似文献   

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在用广义Vandermonde行列式给出Hermite插值多项式的表达式的基础上,分别针对iα=2,iα=3(i=1,2,…,s)的情形给出切触有理插值问题有解的条件及解的表达式.  相似文献   

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文章给出了对于矩形网格上基于二元Newton插值公式的二元向量值有理插值存在性的充要条件.在存在的情况下,建立了具有显式表达式的不同于向量连分式的二元向量值有理插值函数,并且这种方法具有承袭性.最后给出的实例说明了这种算法的有效性.  相似文献   

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该文给出线性系统(dx/dt)=A(t)x具有广义指数型二分性一个充分条件,作为应用研究非线性扰动系统的有界解的存在性. 推广了[1]与[2]结果.  相似文献   

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For a sequence of continuous linear operators on a separable Fréchet space , we discuss necessary conditions and sufficient conditions for to be topologically mixing, and the relations between topological mixing and the Hypercyclicity Criterion. Among them are: 1) topological mixing is equivalent to being hereditarily densely hypercyclic; 2) the Hypercyclicity Criterion with respect to the full sequence implies topological mixing; 3) topological mixing implies the Hypercyclicity Criterion with respect to some sequence that cannot be syndetic in general, and also implies condition (b) of the Hypercyclicity Criterion with respect to the full sequence. Applications to two examples of operators on the Fréchet space of entire functions are also discussed.

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9.
Suppose that K is a compact set in the open complex plane. In this paper, we prove an existence criterion for an estimate of Markov-Bernstein type for derivatives of a rational function R(z) at any fixed point z 0K. We prove that, for a fixed integer s, the estimate of the form |R (s) (z 0)| ≤ C(K, z 0, s)nR C(K), where R is an arbitrary rational function of degree n without poles on K and C is a bounded function depending on three arguments K, z 0, and s, holds if and only if the supremum $$\omega (K,z_0 ,s) = \sup \left\{ {\frac{{\operatorname{dist} (z,K)}}{{\left| {z - z_0 } \right|^{s + 1} }}} \right\}$$ over z in the complement of K is finite. Under this assumption, C is less than or equal to const ·s!ω(K, z 0, s).  相似文献   

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Gaisin  R. A. 《Mathematical Notes》2021,110(5-6):666-678
Mathematical Notes - Problems of constructing regular majorants for sequences $$\mu=\{\mu_n\}_{n=0}^{\infty}$$ of numbers $$\mu_n\ge0$$ that are the Taylor coefficients of integer transcendental...  相似文献   

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在这篇文章, 我们研究了一分数阶基尔霍夫问题, 在一些适当的条件下, 得到了非平凡非负基态解的存在性.  相似文献   

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In this paper we consider the existence of ground states for some 2- coupled nonlinear Schrodinger systems with or without potentials. Under various conditions on the parameters in the equations, we prove the existence of ground states.  相似文献   

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The existence and uniqueness of positive steady states for the age-structured MSEIR epidemic model with age-dependent transmission coefficient is considered. Threshold results for the existence of endemic states are established; under certain conditions, uniqueness is also shown.  相似文献   

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