Iridium(III) complexes formed by O-H and/Or C-H activation of 2-(arylazo)phenols |
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Authors: | Acharyya Rama Basuli Falguni Wang Ren-Zhang Mak Thomas C W Bhattacharya Samaresh |
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Institution: | Department of Chemistry, Inorganic Chemistry Section, Jadavpur University, Kolkata 700 032, India. |
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Abstract: | Reaction of 2-(arylazo)phenols with Ir(PPh(3))(3)Cl] in refluxing ethanol in the presence of a base (NEt(3)) affords complexes of three different types, viz. Ir(PPh(3))(2)(NO-R)(H)Cl] (R = OCH(3), CH(3), H, Cl and NO(2)), Ir(PPh(3))(2)(NO-R)(H)(2)] and Ir(PPh(3))(2)(CNO-R)(H)]. Structures of the Ir(PPh(3))(2)(NO-Cl)(H)Cl], Ir(PPh(3))(2)(NO-Cl)(H)(2)] and Ir(PPh(3))(2)(CNO-Cl)(H)] complexes have been determined by X-ray crystallography. In the Ir(PPh(3))(2)(NO-R)(H)Cl] and Ir(PPh(3))(2)(NO-R)(H)(2)] complexes, the 2-(arylazo)phenolate ligands are coordinated to the metal center as monoanionic bidentate N,O-donors, whereas in the Ir(PPh(3))(2)(CNO-R)(H)] complexes, they are coordinated to iridium as dianionic tridentate C,N,O-donors. In all three products formed in ethanol, the two PPh(3) ligands are trans. Reaction of 2-(arylazo)phenols with Ir(PPh(3))(3)Cl] in refluxing toluene in the presence of NEt(3) affords complexes of two types, viz. Ir(PPh(3))(2)(CNO-R)(H)] and Ir(PPh(3))(2)(CNO-R)Cl]. Structure of the Ir(PPh(3))(2)(CNO-Cl)Cl] complex has been determined by X-ray crystallography, and the 2-(arylazo)phenolate ligand is coordinated to the metal center as a dianionic tridentate C,N,O-donor and the two PPh(3) ligands are cis. All of the iridium(III) complexes show intense MLCT transitions in the visible region. Cyclic voltammetry shows an Ir(III)-Ir(IV) oxidation on the positive side of SCE and an Ir(III)-Ir(II) reduction on the negative side for all of the products. |
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