Syntheses and Crystal Structures of PbSbO2Br,PbSbO2I,and PbBiO2Br

Transparent single crystals of PbSbO₂Br (green), PbSbO₂I, and PbBiO₂Br (yellow) were obtained by solid state reactions of stoichiometric amounts of PbO, Pn₂O₃ (Pn = Sb, Bi) and PnX₃ (X = Br, I). The crystal structures were determined from single‐crystal X‐ray data. The title compounds crystallize tetragonally in the space group I4/mmm (No. 139): Lattice constants and refinement values are: PbSbO₂Br: a = 3.9463(3), c = 12.849(1) Å, V = 200.10(3) Å³, and Z = 2, R₁ = 0.0236, and wR₂ = 0.0513. PbSbO₂I: a = 4.0074(3), c = 13.627(2) Å, V = 218.84(3) Å³, and Z = 2, R₁ = 0.0244, and wR₂ = 0.0538. PbBiO₂Br: a = 3.9818(2), c = 12.766(2) Å, V = 202.39(4) Å³, and Z = 2, R₁ = 0.0276, and wR₂ = 0.0715. The compounds are isotypic and crystallize in the anti‐ThCr₂Si₂ structure type with lead and Pn statistically disordered on one common position. In case of Pn = Sb a slight separation of the positions of the cations becomes obvious. Optical bandgaps were determined by UV/Vis spectroscopy. They are 2.67 eV (PbSbO₂Br), 2.48 eV (PbSbO₂I), and 2.47 eV (PbBiO₂Br).