首页 | 本学科首页   官方微博 | 高级检索  
     检索      


Parity anomaly in a \mathcal{P}\mathcal{T}-symmetric quartic Hamiltonian
Authors:Carl M Bender
Institution:(1) Physics Department, Washington University, St. Louis, MO 63130, USA
Abstract:In this paper, two independent methods are used to show that the non-Hermitian 
$$\mathcal{P}\mathcal{T}$$
-symmetric wrong-sign quartic Hamiltonian H = (1/2m)p 2gx 4 is exactly equivalent to the conventional Hermitian Hamiltonian 
$$\tilde H = ({1 \mathord{\left/ {\vphantom {1 {2m}}} \right. \kern-\nulldelimiterspace} {2m}})p^2  + 4gx^4  - \hbar ({{2g} \mathord{\left/ {\vphantom {{2g} m}} \right. \kern-\nulldelimiterspace} m})^{{1 \mathord{\left/ {\vphantom {1 2}} \right. \kern-\nulldelimiterspace} 2}} x$$
. First, this equivalence is demonstrated by using elementary differential-equation techniques and second, it is demonstrated by using functional-integration methods. As the linear term in the Hermitian Hamiltonian 
$$\tilde H$$
is proportional to ℏ, this term is anomalous; that is, the linear term in the potential has no classical analog. The anomaly is a consequence of the broken parity symmetry of the original non-Hermitian 
$$\mathcal{P}\mathcal{T}$$
-symmetric Hamiltonian. The anomaly term in 
$$\tilde H$$
remains unchanged if an x 2 term is introduced into H. When such a quadratic term is present in H, this Hamiltonian possesses bound states. The corresponding bound states in 
$$\tilde H$$
are a direct physical measure of the anomaly. If there were no anomaly term, there would be no bound states.
Keywords:" target="_blank">          
gif" alt="   $$\mathcal{P}\mathcal{T}$$   " target="_blank">" align="middle" border="0">          symmetry  anomaly  non-Hermitian  parity reflection  time reversal
本文献已被 SpringerLink 等数据库收录!
设为首页 | 免责声明 | 关于勤云 | 加入收藏

Copyright©北京勤云科技发展有限公司  京ICP备09084417号