Ba2SiO4:Ce3+,Mn2+荧光粉的制备与光谱性质

用高温固相反应法合成了Ba₂SiO₄:xCe³⁺,yMn²⁺(x=0~0.2, y=0~0.15)荧光粉,研究了荧光粉的晶体结构和发光性质。在紫外光激发下,Ba₂SiO₄:xCe³⁺的发射光谱为位于384 nm附近的宽带。Ba₂SiO₄:Mn²⁺样品的发射光谱位于376 nm的宽带较强,红光发射极弱。在Ce³⁺和Mn²⁺共掺的Ba₂SiO₄:xCe³⁺,yMn²⁺样品中,位于606 nm附近的红光发射较强,来源于Mn²⁺的⁴T₁(⁴G)-⁶A₁(⁶S)跃迁。这说明Ce³⁺离子将部分能量传递给了Mn²⁺离子,有效地敏化了Mn²⁺离子的发光。当Ce³⁺的摩尔分数为0.2、Mn²⁺的摩尔分数为0.075时,Ba₂SiO₄:xCe³⁺,yMn²⁺荧光粉位于606 nm的Mn²⁺的发射峰最强。

Preparation and Photoluminescence Properties of Ba2SiO4:Ce3+,Mn2+ Phosphor

The phosphors Ba₂SiO₄:xCe³⁺,yMn²⁺(x=0-0.2, y=0-0.15) were synthesized through the solid-state reaction technique. The structure, photoluminescence properties of these phosphors were described. Under the excitation of UV light, the emission spectra of Ba₂SiO₄:xCe³⁺ show broad band around 384 nm. The emission spectra of Ba₂SiO₄: Mn²⁺ show broad band around 376 nm, and the red emission is very weak. The red emission band located at around 606 nm is strongly enhanced in Ba₂SiO₄:xCe³⁺,yMn²⁺, which is arised from ⁴T₁(⁴G)-⁶A₁(⁶S) transition of Mn²⁺. The results show that a part of the energy of Ce³⁺ ion is transferred to Mn²⁺ ion and sensitizes the luminescence of Mn²⁺ ion effectively. When the mole fractions of Ce³⁺ and Mn²⁺ are 0.2 and 0.075, the red emission around 606 nm is the strongest.