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套链分解
引用本文:张华军.套链分解[J].数学研究及应用,2008,28(1):39-45.
作者姓名:张华军
作者单位:Department of Applied Mathematics, Dalian University of Technology, Liaoning 116024, China
摘    要:Let X1,X2,...,Xk be k disjoint subsets of S with the same cardinality m.Define H(m,k) = {X (C) S: X (C) Xi for 1 ≤I ≤k} and P(m,k) = {X (C) S : X ∩ Xi ≠φ for at least two Xi's}.Suppose S = Uki=1 Xi,and let Q(m,k,2) be the collection of all subsets K of S satisfying|K ∩ Xi|≥ 2 for some 1 ≤ I ≤ k.For any two disjoint subsets Y1 and Y2 of S,we define F1,j = {X (C) S : either |X ∩ Y1|≥ 1 or |X ∩ Y2|≥ j}.It is obvious that the four posers are graded posets ordered by inclusion.In this paper we will prove that the four posets are nested chain orders.

关 键 词:poser  normalized  matching  property  sperner  property  nested  chain  decomposition  链分解  Order  Chain  paper  prove  nested  chain  four  ordered  inclusion  collection  subsets  cardinality
收稿时间:2005-12-26
修稿时间:2006-03-02

Nested Chain Order
ZHANG Hua-jun.Nested Chain Order[J].Journal of Mathematical Research with Applications,2008,28(1):39-45.
Authors:ZHANG Hua-jun
Institution:Department of Applied Mathematics, Dalian University of Technology, Liaoning 116024, China
Abstract:Let X1,X2,...,Xk be k disjoint subsets of S with the same cardinality m.Define H(m,k) = {X (C) S: X (C) Xi for 1 ≤I ≤k} and P(m,k) = {X (C) S : X ∩ Xi ≠φ for at least two Xi's}.Suppose S = Uki=1 Xi,and let Q(m,k,2) be the collection of all subsets K of S satisfying|K ∩ Xi|≥ 2 for some 1 ≤ I ≤ k.For any two disjoint subsets Y1 and Y2 of S,we define F1,j = {X (C) S : either |X ∩ Y1|≥ 1 or |X ∩ Y2|≥ j}.It is obvious that the four posers are graded posets ordered by inclusion.In this paper we will prove that the four posets are nested chain orders.
Keywords:poset  normalized matching property  sperner property  nested chain decomposi-tion  
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