Das Gleichgewicht CuCl2,f + Al2Cl6,g = CuAl2Cl8,g und die beteiligten Nebenreaktionen

Equilibrium CuCl_2,f + Al₂Cl_6,g = CuAl₂Cl_8,g and the Side Reactions Aim was the measurement of the equilibrium by the flow method. The following observations have been made:

• (a) The solid CuCl₂ phase dissolves 1 mol% CuCl.
• (b) Measurements with CuAl₂Cl₈ as solid phase confirmed this formula for the gas molecule.
• (c) At constant temperature and by variation of P(Al₂C1₆) the expression ΣP(Cu)/P(Al₂Cl₆) passes a flat minimum. This effect is caused by the fact that in the gas phase small concentrations of CuAlCl₅ and CuAl₃Cl₁₁ are present besides the main complex CuAl₂Cl₈. For the formation equilibrium of these side complexes rough thermodynamic data have been given.
• (d) Taking into account the gas molecules Cl₂…Cu₃AlCl₆ (see above) data for the equilibrium (12) have been ascertained, ΔS₁₂°(590) = 8.64 kcal; ΔS₁₂°(590) = 11.24 cal/K.