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关于Diophantine方程x3+1=py2
引用本文:高洁,袁进. 关于Diophantine方程x3+1=py2[J]. 纯粹数学与应用数学, 2010, 26(4): 687-690. DOI: 10.3969/j.issn.1008-5513.2010.04.027
作者姓名:高洁  袁进
作者单位:西北大学数学系,陕西,西安,710127;西北大学数学系,陕西,西安,710127
摘    要:在素数p=3(8t+4)(8t+5)+1和p=3(8t+3)(8t+4)+1的情形下,运用初等数论的方法给出了丢番图方程x3+1=py2无正整数解的充分条件,并得到无数个6k+1型的素数p使得方程x3+1=py2无正整数解.

关 键 词:丢番图方程  正整数解  奇素数  同余

On the Diophantine equation x3 + 1 =py2
GAO Jie,YUAN Jin. On the Diophantine equation x3 + 1 =py2[J]. Pure and Applied Mathematics, 2010, 26(4): 687-690. DOI: 10.3969/j.issn.1008-5513.2010.04.027
Authors:GAO Jie  YUAN Jin
Affiliation:GAO Jie 1,YUAN Jin 2(Department of Mathematics,Northwest University,Xi'an 710127,China)
Abstract:Using elementary theory of numbers methods,a sufficient condition is obtained that the Diophantine equation x3+1 = py2 has no positive integer solution,where p = 3(8t+4)(8t+5)+1 and p = 3(8t+3)(8t+4)+1.And get countless p,where p is an odd prime of the form 6k+1,meet the equation x3+1 = py2 without positive integer solution.
Keywords:Diophantine equation  positive integer solution  odd prime  recurrent sequent  
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