K0.5Na0.5NbO3-LiSbO3-BiFeO3/CuFe2O4复合陶瓷的制备与磁电性能研究

采用传统的固相法制备了(1-x)(K_0.5Na_0.5NbO₃-LiSbO₃-BiFeO₃)-xCuFe₂O₄ (x=0.1, 0.2, 0.3, 0.4) 磁电复合陶瓷, 并借助X射线衍射仪、扫描电镜和磁电耦合系数测试仪等对复合陶瓷的微结构和性能进行了分析. 结果表明, 复合陶瓷的K_0.5Na_0.5NbO₃-LiSbO₃-BiFeO₃和CuFe₂O₄物相之间发生了一定的离子相互扩散作用, 且两相的颗粒大小匹配性较好. 随着CuFe₂O₄含量增加, 复合陶瓷的压电系数从130 pC/N减小到30 pC/N, 饱和磁致伸缩系数从4.5×10^-6增加到12.4×10^-6左右, 磁电耦合系数表现出先增加后减小, 在x=0.3时获得最大的磁电耦合系数9.4 mV·cm^-1·Oe^-1. 关键词： 0.5Na_0.5NbO₃-LiSbO₃-BiFeO₃')" href="#">K_0.5Na_0.5NbO₃-LiSbO₃-BiFeO₃ 2O₄')" href="#">CuFe₂O₄ 磁电耦合

Preparation and magnetoelectric characteristics of K0.5Na0.5NbO3-LiSbO3-BiFeO3/CuFe2O4 composite ceramics

The (1-x)(K_0.5Na_0.5NbO₃-LiSbO₃-BiFeO₃)-xCuFe₂O₄ (x=0.1, 0.2, 0.3 and 0.4) magnetoelectric composite ceramics are prepared by the conventional solid-state reaction method. The microstructures and properties of the composite ceramics are characterized by X-ray diffractometer, scanning electron microscope and magnetoelectric coupling coefficient meter. The weak ionic interdiffusions between the phases K_0.5Na_0.5NbO₃-LiSbO₃-BiFeO₃ and CuFe₂O₄ are observed and their particle sizes are well matched between each other. With the increase of CuFe₂O₄ content, the piezoelectric coefficient (d₃₃) of the composite ceramics decreases from 130 pC/N to 30 pC/N and the magnetostriction coefficient (-λ) increases from 4.5×10^-6 to 12.4×10^-6. The magnetoelectric coupling coefficient (α_E) of the composite ceramics first increases and then decreases with the CuFe₂O₄ content increasing. When the composition x=0.3, a maximum value of α_E=9.4 mV·cm^-1·Oe^-1 is achieved.