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Let F be a family of functions meromorphic in a domain D, let n ≥ 2 be a positive integer, and let a ≠ 0, b be two finite complex numbers. If, for each f ∈ F, all of whose zeros have multiplicity at least k + 1, and f + a(f^(k))^n≠b in D, then F is normal in D. 相似文献
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Letfbeanon-linearmeromorphicfunctiondefinedinthecomplexplaneC.TheFatousetF(f)offisthelargestsubsetofCwheretheiteratesf"offformanormalfamily.ThecomplementofF(f)iscalledtheJuliasetanddenotedbyJ(f).IfUisacomponentofF(f),thenf"(U)iscontainedinsomecomponentofF(f)whichwedenotebyUn.IfUnnUrn=.foralln/m,thenUiscalledwandering.OtherwiseUiscalledeventuallyperiodic.Inparticular,ifUk=UforsomepENandUrn/Ufor0Sm
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设f为超越亚纯函数, a为非零有穷复数, n(≥ 2)为正整数, 则f+a(f′)n取每一个复数无穷多次. 当n=2时回答了叶亚盛的一个问题. 同时给出了相应的正规定则. 相似文献
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设 f 为非常数亚纯函数, n(≥ 4)为正整数, a 为非零有穷复数. 若a 为f n与 (f n)′ 的CM分担值, 则nf ’=f. 相似文献
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OnaProblemofHaymanChenHuaihui(陈怀惠)FangMingliang(方明亮)(DepartmentofMathematics,NanjingNormalUniversity,Nanjing,Jiangsu,210024)C... 相似文献
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Let f be a meromorphic function of finite order in the plane. If its Nevanlinnadeficiency sum is 2,then we say that f has maximum deficiency sum. Drasin con-jectured that if f has maximum deficiency sum and the infinity is not its Nevanlinna'sdeficient value, then zero is the only Nevaulinna's deficient value of f' with defi-ciency 1. Yang Lo gave a positive answer of this conjecture by proving that under theabove assumption, zero is the only Nevanlinna's deficient value of f(h) with,deficie-ncy 2/(1 + k) for k = 1,2,…. Now, omitting the condition δ(∞,f) = 0, we prove 相似文献
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