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1.
There exists a non-Dunford-Pettis operator fromL 1 into a Banach latticeE that does not contain a copy ofc 0 orL 1. This problem is related to regularisation properties of convolution operators onL 1. Work partially supported by an N.S.F. Grant.  相似文献   
2.
Consider a random Hamiltonian HN(σ) for σ∈ΣN={0,1}N. We assume that the family (HN(σ)) is jointly Gaussian centered and that for σ1,σ2∈ΣN,N?1EHN(σ1)HN(σ2) =ξ(N?1i?Nσ1iσ2i) for a certain function ξ on R. F. Guerra proved the remarkable fact that the free energy of the system with Hamiltonian HN(σ)+h∑i?Nσi is bounded below by the free energy of the Parisi solution provided that ξ is convex on R. We prove that this fact remains (asymptotically) true when the function ξ is only assumed to be convex on R+. This covers in particular the case of the p-spin interaction model for any p. To cite this article: M. Talagrand, C. R. Acad. Sci. Paris, Ser. I 337 (2003).  相似文献   
3.
We prove that the suitably defined surface area of a subsetA of the cube {0,1} n is bounded below by a certain explicit function of the size ofA. We establish a family of logarithmic Sobolev inequalities on the cube related to this isoperimetric result. We also give a quantitative version of Margulis' graph connectivity theorem.Work partially supported by the US-Israel Binational Science Foundation.  相似文献   
4.
We compute at any temperature the free energy of the multi p-spin spherical model when only terms for p even are considered. Work partially supported by an NSF grant  相似文献   
5.
Summary Forq>2, an operator fromC(K) toX is of cotypeq if and only if it factors through the Lorentz space . Forq=2, ifX is a rearrangement invariant space on [0, 1], the injectionC([0, 1])X is of cotype 2 if and only if it factors through the Lorentz space ; but there is a cotype 2 operator C(K) that does not factor through . If a Banach latticeX satisfies the Orlicz property, any bounded lattice operatorT:C(K)X is of cotype 2. We however construct a Banach lattice with the Orlicz property, but that fails to be of cotype 2.Oblatum 4-VII-1990 & 18-IV-1991Work partially supported by an NSF grant  相似文献   
6.
Consider a (complex) Banach spaceX, such thatX CO, and vectors(X i ) i ofX. Consider an independent standard normal sequence(g i ) i . Then if anX-valued random Fourier series |k| n e ikt g k x k satisfies
  相似文献   
7.
Summary We give a simple proof of the fact that a Radon gaussian measure on a locally convex vector space is carried by a countable union of metrisable compact sets. We show that a separable centered gaussian process with continuous covariance which is defined on a Polish space X, and is a.e. unbounded on any open set, has a.e. dense trajectories in X × . These results allow us to show that for any set I, any gaussian measure on I is -smooth.  相似文献   
8.
Resumé On construit un groupe compact et une sous-mesure pathologique sur ce groupe dont la convolée avec la mesure de Haar n'est pas pathologique.  相似文献   
9.
Consider 0<α<1 and the Gaussian process Y(t) on ℝ N with covariance E(Y(s)Y(t))=|t|+|s|−|ts|, where |t| is the Euclidean norm of t. Consider independent copies X 1,…,X d of Y and␣the process X(t)=(X 1(t),…,X d (t)) valued in ℝ d . When kN≤␣(k−1)αd, we show that the trajectories of X do not have k-multiple points. If Nd and kN>(k−1)αd, the set of k-multiple points of the trajectories X is a countable union of sets of finite Hausdorff measure associated with the function ϕ(ɛ)=ɛ k N /α−( k −1) d (loglog(1/ɛ)) k . If Nd, we show that the set of k-multiple points of the trajectories of X is a countable union of sets of finite Hausdorff measure associated with the function ϕ(ɛ)=ɛ d (log(1/ɛ) logloglog 1/ɛ) k . (This includes the case k=1.) Received: 20 May 1997 / Revised version: 15 May 1998  相似文献   
10.
Letτ be a cardinal with cf(τ)>ℵ0. Then a Banach spaceE contains a subspace isomorphic tol l(τ) if and only if [0,1] r is a continuous image of the unit ballE1 ofE′, provided with the w*-topology. It follows that, for each cardinalκ, ifE1 contains a copy ofβκ, thenE has a quotient isomorphic tol (κ). In this situation we show thatE has even a quotientisometric tol (κ).   相似文献   
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