Hardy-Hilbert型不等式的一个加强

改进了Hlder不等式,并利用加强的Hlder的不等式对联系β函数的带参数的Hardy-Hilbert型不等式进行了改进,建立一个新的形如sum from n=1 to ∞ sum from m=1 to ∞(ambn/(m+n)λ)/相似文献   

Hardy-Riesz拓广了的Hilbert不等式的一个改进

Let {a_n} and {b_n}be any two sequences of non-negative numbers such that 01).Then Hardy-Riesz′s extension of the Hilbert inequality can be sharpened to the form     

The series sum from(n=1) to ∞(1/(n~(k 1))e(-z~(2k))/(n~(2k)))(oddk) and Riemann Zeta function

J.Tennenbaum discussed the function sum from n=1 to ∞() 1/n~2 e~(-2/n) in 1977.Zhang Nanyue discussed the function sum from n=1 to 1 () 1/n~2e~(-z~2/n~2) in 1983.Now we discuss the functions sum from n=1 to ∞ () 1/n~(k 1).e~(z~(2k)/n~(2k))(kpositive odd)in this paper which finds representations of two integrales about Riemann Zeta function     

样本均值幂级数的收敛性

摘要设X_1,X_2,…为iid.,EX_1=0,0相似文献   

Use Cesro Means To Describe Two Classes of Functions

Let H(D)be the collection of functions which are analytic in the unitdisc D.we call B_0={f∈H(D),(?)(1-|z|~2)|f’(z)|=0}litlle Bloch space.Letf∈H(D),0相似文献   

On the Best Degree of Approximation by Euler (E,q)-Means

Let f(x)∈L_(2π) and its Fourier series by f(x)～α_0/2+sum from n=1 to ∞(α_ncosnx+b_nsinx)≡sum from n=0 to ∞(A_n(x)). Denote by S_n (f,x) its partial sums and by E_n~q(f,x) its Euler (E, q)-means, i. e. E_n~q(f,x)=1/(1+q)~π sum from m=0 to n((?)q~(n-m)S_m(f,x)), with q≥0 (E_n~0≡S_n). In [1] Holland and Sahney proved the following theorem. THEOREM A Ifω(f,t) is the modulus of continuity of f∈C_(2π), then the degree of approximation of f by the (E,q)-means of f is givens by##特殊公式未编改     

一个有极限的单调增加数列

证明了{n(16n~2+4n+3)/16n~2-4~n+3~(1/2) integral from 0 to π/2 sin~nxdx}为严格单调增加数列,且极限为π/2~(1/2),因而得π(16n~2+36n+23)/2(n+1)(16n~2+28n+15)~(1/2)integral from 0 to π/2 sin~nxdxπ(16n~2-4n+3)/2n(16n~2+4n+3)~(1/2).     

THE NATURAL BOUNDARY OF SOME RANDOM POWER SERIES

Suppose that {X_n(ω)} are independent random complex variable sequence, E(X_n)-0 and Then the circle {|Z|=ρ} is almost surely a natural boundary of the random series sum from n=1 to ∞ X_n(ω)Z~(n-1)     

关于Littlewood的一个问题

本文证明了: (1)如果{a_n}_n~N=1是非负不减序列,p>0,q>0,0≤r≤1,且p(q+r)≥q+p,则sum from n=1 to N(a_n~pA_n~q)(sum from m=n to N(a_n~(1+p/q)~r≤1·sum from n=1 to N(a_n~pA_n~q)~(1+p/q),其中A_n=sum from m=n to n (a_m).上述不等式在0≤r≤1时完全解决了H.Alzer~([4])在1996年提出的一个问题,且1是最佳常数; (2)如果{a_n}_n~N=1是非负序列,p,p≥1,r>0,r(p-1)≤2(q-1),令α=((p-1)(q+r)+p~2+1)/(p+1) β=(2p+2r+p-1)/(q+1),σ=(q+r-1)/(p+q+r)则sum from n=1 to N (a_n~p)sum from i=1 to n (a_i~qA_i~r)≤2~σsum from n=1 to N(a_n~αA_n~β)(0.2)(0.2)式改进了G.Be(?)et~([2,3])在1987年对Littlewood一个问题的结果,常数因子的3/2降为2~(3/2)=1.2598…     

关于线性过程谱函数估计的弱不变原理的一点注记

设随机序列{X_n; n=0,±1…}可表示成为X_n=sum from j=-∞ to +∞(α_(j-n)ζ_j其中{α_j}是满足sum from j=-∞ to +∞(α_j~2)<∞的实数列,{ζ_j}是白噪声序列。通常用(?)_N(λ)=integral from 0 to λ(1/2πN)∣sum from k=1 to N(x_(?)e~(iμk)∣~2 dμ来估计{x_n}的未知的谱函数F(λ)。在一定的条件下,当{ζ_j}是独立同分布随机序列时,和[3]证明了:过程√(?)[(?)_N(λ)-F(λ)]的分布弱收敛到某个正态过程ζ(λ)在C[0,π]上产生的测度。本文在他们工作的基础上,运用鞅的极限定理和鞅不等式,改进了[3]中的两个关键引理,从而证明了当{ζ_j}是有控制分布的实四阶鞅差序列时,仍有相同的结果。