共查询到20条相似文献,搜索用时 109 毫秒
1.
令k≥1是一个整数.在黎曼猜想成立的条件下,本文给出了n=p1k+p23+p33+p34+p53平均表法个数的一个合适的渐近公式,其中p1,p2,p3,p4,p5都是素数,推广了之前的结果. 相似文献
2.
H表示一个正整数N的集合,使对任意的正整数q,同余方程a+b~2≡N(mod q)在模q的既约剩余系中有解a;b.E(x)表示N≤x,N∈H,但不能表成p_1+p_2~2=N的数的个数,其中p_1,p_2个表示素数,则E(x)<相似文献
3.
吕晓东 《数学年刊A辑(中文版)》2015,36(2):161-174
令P_r表示素因子不超过r的殆素数,按重数计.作者证明了对于充分大的偶数N,方程N=x~2+p_1~2+p_2~3+p_3~3+p_4~4+p_5~4有解,其中x是殆素数P_6,p_j(j=1,…,5)是素数. 相似文献
4.
本文证明了最多有O(N13/30+ε)个例外之外,所有的正的奇整数n≤N,n≡0或1(mod 3)能表示成一个素数和两个素数的平方和. 相似文献
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6.
设G(k)为所有充分大的正整数均可表示为不超过s个正整数k次方幂之和的最小s.本文对G(12),G(13),G(19)给出了新的估计. 相似文献
7.
设N为充分大的整数.本文证明了对于不超过N且满足某些必要同余条件的正整数n除至多O(N17/18+ε)之外均可以表示为p13+p24+p34+p44+p54+p64+p74+p84+p94+p104的形式,其中p1,p2,…,p10为素数. 相似文献
8.
设k≥2,且Hk表示一个正整数n的集合,使得该集合中的元素满足a+bk≡n(modq)对任意的q,在模q的既约剩余系中有解,令Dk(N)表示所有的n≤N,且n∈Hk且不能表成p1+p2k=n形式的整数.那么在GRH下, Dk(N)相似文献
9.
设A(n)为von Mangoldt函数且实数θ=95-83~(1/2)/121.当xθ+ε≤y≤x时,本文对于所有的α∈[0,1]给出了指数和S2(x,y;α)=∑x0,估计式∑x相似文献
10.
设k≥2,Hk表示一个正整数n的集合,使对任意的正整数q,同余方程a+b2三n(modq)在模q的既约剩余系中有解a,b.Dk(N)表示n≤N,n∈Hk,但不能表成p1+p22=n的数的个数,其中p1,p2表示素数.则在GRH下,Dk(N)<<N1-1/k(h(k)+1)+ε,这里k=2,3;h(2)=2,h(3)=8. 相似文献
11.
On sums of a prime and four prime squares in short intervals 总被引:1,自引:0,他引:1
Xian-Meng Meng 《Acta Mathematica Hungarica》2004,105(4):261-283
12.
On sums of a prime and four prime squares in short intervals 总被引:1,自引:1,他引:0
In this paper, we prove that each sufficiently large integer N ≠1(mod 3) can be written as N=p+p1^2+p2^2+p3^2+p4^2, with
|p-N/5|≤U,|pj-√N/5|≤U,j=1,2,3,4,
where U=N^2/20+c and p,pj are primes. 相似文献
|p-N/5|≤U,|pj-√N/5|≤U,j=1,2,3,4,
where U=N^2/20+c and p,pj are primes. 相似文献
13.
Exponential sums over primes in short intervals 总被引:3,自引:0,他引:3
LIU Jianya Lu Guangshi & ZHAN Tao Department of Mathematics Shandong University Jinan China 《中国科学A辑(英文版)》2006,49(5):611-619
In this paper we establish one new estimate on exponential sums over primes in short intervals. As an application of this result, we sharpen Hua's result by proving that each sufficiently large integer N congruent to 5 modulo 24 can be written as N = p12 p22 p32 p42 p52, with |pj-(N/5)~(1/2)|≤U = N1/2-1/20 ε, where pj are primes. This result is as good as what one can obtain from the generalized Riemann hypothesis. 相似文献
14.
Guangshi Lü 《Journal of Number Theory》2008,128(4):805-819
In this paper, we are able to sharpen Hua's classical result by showing that each sufficiently large integer can be written as
15.
孟宪荫 《纯粹数学与应用数学》2005,21(4):378-384
设N是充分大的奇数,本文在广义Riemman 假设下证明了方程N=p1 p2 p3,pi-(N/3)≤U, i=1,2,3, U≥N(1/2)logN3 ε有解,此处pi是素数,并得到了方程解数的渐进式. 相似文献
16.
Let Λ(n) be the von Mangoldt function, x real and y small compared with x. This paper gives a non-trivial estimate on the exponential sum over primes in short intervals
for all α ∈ [0,1] whenever
. This result is as good as what was previously derived from the Generalized Riemann Hypothesis. 相似文献
17.
Let Λ(n) be the von Mangoldt function, x real and y small compared with x. This paper gives a non-trivial estimate on the exponential sum over primes in short intervals
S2(x,y;a)=?x < n £ x+yL(n)e(n2 a)S_2(x,y;{\alpha})=\sum_{x < n \le x+y}\Lambda(n)e(n^2 {\alpha})
for all α ∈ [0,1] whenever
x\frac23+e £ y £ xx^{\frac{2}{3}+{\varepsilon}}\le y \le x
. This result is as good as what was previously derived from the Generalized Riemann Hypothesis. 相似文献
18.
Let λ1, λ2, λ3, λ4 be non-zero real numbers, not all of the same sign, w real. Suppose that the ratios λ1/λ2, λ1/λ3 are irrational and algebraic. Then there are in.nitely many solutions in primes pj, j =1, 2, 3, 4, to the inequality . This improves the earlier result. 相似文献
19.
Let H2{\mathcal H_2} denote the set of even integers
n \not o 1 mod 3{n \not\equiv 1 \pmod 3} . We prove that when H ≥ X
0.33, almost all integers n ? H2 ?(X, X + H]{n \in \mathcal H_2 \cap (X, X + H]} can be represented as the sum of a prime and the square of a prime. We also prove a similar result for sums of three squares
of primes. 相似文献
20.